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Alex Ar [27]
3 years ago
7

48 cookies; 25 % decrease... Find the new amount given the original amount And the percent of change.

Mathematics
1 answer:
coldgirl [10]3 years ago
7 0
48 cookies after 25 % decrease is as much as 75 % from 48:

75% from 48 =
= 75/100 * 48 =
= 3/4 * 48 =
= 3/1 * 12 =
= 3  * 12 =
= <u>36
</u>

I hope it will help you :)
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Give the domain and range of the relation. Indicate whether the relation is a function or not.
rewona [7]

D: {0, 1, 2, 3}

R: {−3, −2, 2, 5}

The relation is a function.

That's the answer.

4 0
2 years ago
8. What is the solution to the equation 3x + 5(4x-6)-8= 3x - 14? a. x = 1 b. r = 1.7 d. There are no solutions to this equation.
Verdich [7]

3x+5(4x-6)-8=3x-14

Step-by-step explanation:

Cancel out the terms on both sides of the equation. (3x)

5(4x-6)-8=-14

Distribute 5 through the parentheses.

20x-30-8=-14

Calculate the difference.

20x-38=-14

Move the constant to the right-hand side and change its sign.

20x=-14+28

Calculate the sum.

20x=24

Divide both sides of the equation by 20.

x=6/5, 1.2, or 1 1/5

Answer:

x=6/5, 1.2, or 1 1/5

Hope this helps! :)

6 0
3 years ago
Choose the value for x that solves this equation. 0 = -2x + 6
lana66690 [7]

<em>Answer:</em>

<em>x = 3</em>

<em>Step-by-step explanation:</em>

<em>Hi there ! </em>

<em>0 = - 2x + 6</em>

<em>2x = 6</em>

<em>x = 6 : 2</em>

<em>x = 3</em>

<em>Good luck !</em>

7 0
3 years ago
PLEASE HELP GIVING BRAINLIEST
Alexeev081 [22]

Answer:

(-5-3/2,3+1/2)

(-13/2,7/2)

option A is correct

Step-by-step explanation:

Hope it helps

4 0
3 years ago
Read 2 more answers
Which technique is most appropriate to use to solve each equation? Drag the name of the technique into the box to match each equ
NemiM [27]
For the first equation, the answer is C) completing the square.
For the second equation, the answer is B) zero product property.

For the first equation, we can easily complete the square by finding half of b and squaring it; then we can take the square root of both sides and solve the equation.

For the second equation, since it is already factored, we use the zero product property to solve it.
7 0
3 years ago
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