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Anastasy [175]
3 years ago
12

Plz help me number 4 thanks

Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0

They \:  would \:  be  - 10°F,  - 13°F, - 21°F

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the Olympic record for the men's 100m freestyle is 47 seconds. the Olympic record for the women's 50m freestyle is 24 seconds. w
Nikolay [14]

Answer:

Step-by-step explanation:

The unit rate of the 100m race is 2.12... m/s which you get by dividing the 100 meters by the 47 seconds. The unit rate for the 50m race is 2.08... m/s which you get by dividing the 50 meters by the 24 seconds. This means that the record for the 100m race is faster.

5 0
3 years ago
HELP any1 good at math?
valentina_108 [34]

Step-by-step explanation:

the equations are :-

=》d = 40m + 200

=》d = 50m

here, by equalising both equations.

( since, d = d )

=》40m + 200 = 50m

=》50m - 40m = 200

=》10m = 200

=》m = 200 ÷ 10

=》m = 20

now,

=》d = 50m

=》d = 50 × 20

=》d = 1000

6 0
2 years ago
How do you simplify <img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B2%7D%20%2B%5Csqrt%7B6%7D%20%7D%7B%5Csqrt%7B8%7D%20%2B%
blondinia [14]

The trick is to exploit the difference of squares formula,

a^2-b^2=(a-b)(a+b)

Set a = √8 and b = √6, so that a + b is the expression in the denominator. Multiply by its conjugate a - b:

(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)=(\sqrt8)^2-(\sqrt6)^2=8-6=2

Whatever you do to the denominator, you have to do to the numerator too. So

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}{(\sqrt8+\sqrt6)(\sqrt8-\sqrt6)}=\dfrac{(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)}2

Expand the numerator:

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{2\cdot8}+\sqrt{6\cdot8}-\sqrt{2\cdot6}-(\sqrt6)^2

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=\sqrt{16}+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=4+\sqrt{48}-\sqrt{12}-6

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(\sqrt4-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6)=-2+\sqrt{12}(2-1)

(\sqrt2+\sqrt6)(\sqrt8-\sqrt6}=-2-\sqrt{12}

So we have

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+\sqrt{12}}2

But √12 = √(3•4) = 2√3, so

\dfrac{\sqrt2+\sqrt6}{\sqrt8+\sqrt6}=-\dfrac{2+2\sqrt3}2=\boxed{-1-\sqrt3}

7 0
2 years ago
5. Find the value of the 11th term of the arithmetic sequence <br> -2, 5, 12, 19, 26, ...(11th term)
ratelena [41]

Answer:

-2, 5, 12, 19, 26, 33, 40, 47, 54, 61, 68, 75, 82, 89, 96, 103

8 0
1 year ago
System of equations<br><br>y=1/2x +5<br>y=3x -5​
Art [367]

Answer: 4

Step-by-step explanation:

Set them equal to each other since they're both equal to y

3x-5=.5x +5

add 5 to both sides

3x=.5x+10

subtract .5x from both sides

2.5x=10

divide both sides by 2.5

x= 4

5 0
2 years ago
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