Answer:
141.4 sq cm
Step-by-step explanation:
to find the area of the outer circle with a smaller circle inscribed within, you find the area of each and subtract the smaller area from the larger
the radius of the smaller circle is 2
we have to find the radius of the larger circle so we use what we know about its circumference:
C = 2πr
43.96 = 2πr
21.98 = πr
21.98 / π = r
r ≈ 7 cm
now use r = 7 to find area of larger circle:
A = πr²
A = π49
Area of smaller circle: 4π
Area of larger circle without including inner section is 49π - 4π = 45π
45π ≈ 141.4 sq cm
Answer: False
Step-by-step explanation: By defintion a midpoint is the middle of the segment, and there canno't e more then one middle of something.
X + 5y = 1 . . . . (1)
8x - 2y = 3 . . . .(2)
Solution 1.
From (1), x = 1 - 5y
substituting for x in (2), we have:
8(1 - 5y) - 2y = 3
8 - 40y - 2y = 3
8 - 42y = 3
42y = 5
y = 5/42
x = 1 - 5(5/42) = 1 - 25/42 = 17/42.
Solution 2.
Multiply (1) by 8, to get:
8x + 40y = 8 . . . . . (3)
(3) - (2) = 40y - (-2y) = 8 - 3
42y = 5
y = 5/42
substitute for y into (3), to get:
8x + 40(5/42) = 8
8x + 100/21 = 8
8x = 8 - 100/21 = 68/21
x = (68/21)/8 = 17/42
Answer:
Point of intersections are (0, -7) and (5, -2).
Step-by-step explanation:
From the graph attached,
A straight line is intersecting the circle at the two points (0, 7) and (5, -2).
Now solve algebraically,
Equation of the line → y = x - 7 -------(1)
Equation of the circle → (x - 5)² + (y + 7)² = 25 -------(2)
By substituting the value of y from equation (1) to equation (2)
(x - 5)² + (x - 7 + 7)² = 25
(x - 5)² + x² = 25
x² - 10x + 25 + x² = 25
2x² - 10x = 0
x² - 5x = 0
x(x - 5) = 0
x = 0, 5
From equation (1),
y = 0 - 7 = -7
y = 5 - 7 = -2
Therefore, point of intersections are (0, -7) and (5, -2).
Answer:
Here
perimeter=76
length =4a+5
breadth=2a-3
we know,
perimeter=2(length+breadth)
76=2(4a+5+2a-3)
76=2(7a+2)
76=14a+4
76-4=14a
72=14a
72÷14=a
a=5.14
