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3 years ago

What are rational numbers that are not integers

1 answer:

7 0

Any number that you can write down on paper ... with digits, a fraction bar,
and a decimal point ... is a rational number.

If it uses only digits, then it's an integer. If it needs a fraction bar or a decimal
point, then it's NOT an integer. But if you can write the whole thing on paper,
without any other symbols or comments, then it's a rational number.

You might be interested in

It is important that face masks used by firefighters be able to withstand high temperatures because firefighters commonly work i

Salsk061 [2.6K]

Answer:

$(-\infty, 0.2661)$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

n=60 represent the sample size

X=12 represent the number of masks that had lenses pop out at 250°

$\hat p =\frac{12}{60}=0.2$ represent the estimated proportion of masks that had lenses pop out at 250°

p represent the population proportion of masks that had lenses pop out at 250°

Confidence =0.9 or 90%

$\alpha=0.1$ represent the significance level

Confidence interval

On this case we want a interval on this form : $(-\infty,\hat p +z_{\alpha}\sqrt{\frac{\hat p (1-\hat p)}{n}})$

So the critical value would be on this case $z_{\alpha}=1.28$ and we can use the following excel code to find it: "=NORM.INV(1-0.1,0,1)"

We found the lower limit like this:

$0.2 +1.28\sqrt{\frac{0.2 (1-0.2)}{60}}=0.2661$

And the interval would be: $(-\infyt, 0.2661)$

3 0

4 years ago

Suppose that scores on a knowledge test are normally distributed with a mean of 60 anda standard deviation of 4.3. Scores on an

Iteru [2.4K]

The Z-score for Boris is 1.627, and the Z-score value for the Callie is 1.267, Boris scored higher relatively.

The Z test is a parametric procedure that is used on data that is dispersed in a normal fashion. For testing hypotheses, the z test can be used on one sample, two samples, or proportions. When the population variance is known, it analyzes if the means of two big groups are dissimilar.

We know the formula for the Z-test:

$\rm Z = \dfrac{X-\mu}{\sigma}$

(a) For Boris:

$\rm Z = \dfrac{67-60}{4.3}$

Z = 1.627

(b) For Callie:

$\rm Z = \dfrac{119-110}{7.1}$

Z = 1.267

(c) Since the measures of two different data have been set to one measure and the value of the Z-score for Boris is higher relative to the Z-score value of Callie so Boris scored higher relatively.

Thus, the Z-score for Boris is 1.627, and the Z-score value for the Callie is 1.267, Boris scored higher relatively.

Learn more about the Z-test here:

brainly.com/question/15683598

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8 0

2 years ago

Can someone please help me?

melamori03 [73]

Answer:

Answer is B

Step-by-step explanation:

3 0