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swat32
2 years ago
13

2=ln(x+7) solve for x

Mathematics
1 answer:
maria [59]2 years ago
8 0

Answer:

e^2 -7 = x

Step-by-step explanation:

2=ln(x+7)

Raise each side to the base of e

e^2 = e^ln (x+7)

The e^ln cancel

e^2 = x+7

Subtract 7 from each side

e^2 -7 = x +7-7

e^2 -7 = x

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0.25*N=24
N=24/0.25
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3 years ago
Read 2 more answers
Explain two ways to find the LCM​
svp [43]

Answer:

1. List the first several multiples of each number.

Look for multiples common to both lists. ...

Look for the smallest number that is common to both lists.

This number is the LCM.

Find the GCF for the two numbers.

Divide that GCF into the either number; it doesn't matter which one you choose, so choose the one that's easier to divide.

Take that answer and multiply it by the other number.

Step-by-step explanation:

Hope this helps!

4 0
3 years ago
Please help! I need to do well on this!
andrey2020 [161]

Answer:

The answer is a

Step-by-step explanation:

4 0
2 years ago
I don't get this one?
Vlad1618 [11]

Answer:

4000

Step-by-step explanation:

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7 0
2 years ago
PLEASE ANSWER
oksano4ka [1.4K]

Answer:

x² + 9x + 8 = (x + 1)(x + 8)

x² + 9x + 8 = (x + 8)(x + 1)

Step-by-step explanation:

* Lets explain how to factorize the polynomial using the pattern

- The form of the quadratic polynomial is x² + px + q, where p is the

  coefficient of x and q is the numerical term

∵ x² + (a + b)x + (ab) = (x + a)(x + b)

- From the formula above the coefficient of x is the sum of the two

 factors a and b

∴ p = a + b and q = ab

- That means p is the sum of two numbers and q is the product of

  the same numbers

* Lets solve the problem

∵ x² + 9x + 8 is a quadratic polynomial

∵ x² + px + q is the form of quadratic polynomial

∴ p = 9 and q = 8

∵ p = a + b and q = ab

∴ a + b = 9 ⇒ (1)

∴ ab = 8 ⇒ (2)

- We must to find two numbers their product is 8 and their sum is 9

∵ The possibility of 8 as a product of two numbers is:

   2 × 4 OR 1 × 8

∵ The sum of 1 + 8 = 9

∴ The value of a and b are 1 and 8

- It does't matter which of them = 1 or which of them = 8

∴ x² + (a + b)x + ab = x² + (1 + 8)x + (1)(9)

∵ x² + (a + b)x + (ab) = (x + a)(x + b)

∴ x² + (1 + 8)x + (1)(9) = (x + 1)(x + 8)

∴ x² + 9x + 8 = (x + 1)(x + 8)

- OR

∴ x² + 9x + 8 = (x + 8)(x + 1)

3 0
2 years ago
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