Which of the following names apply to this number? 2

1 answer:

6 0

You haven't given us any choices to pick from. But I have a feeling that you're not talking about names like Ralph, Bob, or Jacob, so I'll take some guesses from the names of sets that numbers are commonly organized into:

The number ' 2 ' is ...

-- a real number
-- a rational number
-- a positive number
-- an integer
-- a counting number
-- a natural number
-- a whole number
-- a prime number
-- an even number

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√363 - 3√27 simplify the radical expression. Show all your steps please :)

laila [671]

Answer:

3.5

Step-by-step explanation:

Square root 363=19.1

square root 27=5.2

19.1 - 3 x 5.2

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2 years ago

I need the <br> Domain:<br> and <br> Range:

Aleksandr [31]

Answer:

I don't know what kind of form your assignment wants it in, but the domain (span over the x axis) is -4<=x<=5, and the range is -3<=x<=5. Perhaps write it is as "-4 to 5" for domain and "-3 to 5" for range.

Step-by-step explanation:

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1 year ago

jillian calculates that see will take 95 minutes to run 7 miles. she runs the distance in 80 minutes. what is jillians percent e

Aneli [31]

Answer:

15.79%

Step-by-step explanation:

do 95-80 which is 15

then do 15/95 as a fraction then multiply that number by 100 to get 15 15/19 then turn that into a decimal and you get 15.79%

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3 years ago

A box contains 24 transistors,4 of which are defective. If 4 are sold at random,find the following probabilities. i. Exactly 2 a

zavuch27 [327]

SOLUTION

This is a binomial probability. For i, we will apply the Binomial probability formula

i. Exactly 2 are defective

Using the formula, we have

$\begin{gathered} P_x=^nC_x\left(p^x\right?\left(q^{n-x}\right) \\ Where\text{ } \\ P_x=binomial\text{ probability} \\ x=number\text{ of times for a specific outcome with n trials =2} \\ p=\text{ probability of success = }\frac{4}{24}=\frac{1}{6} \\ q=probability\text{ of failure =1-}\frac{1}{6}=\frac{5}{6} \\ ^nC_x=\text{ number of combinations = }^4C_2 \\ n=\text{ number of trials = 4} \end{gathered}$

Note that I made the probability of being defective as the probability of success = p

and probability of none defective as probability of failure = q

Exactly 2 are defective becomes the binomial probability

$\begin{gathered} P_x=^4C_2\times\lparen\frac{1}{6})^2\times\lparen\frac{5}{6})^{4-2} \\ P_x=6\times\frac{1}{36}\times\frac{25}{36} \\ P_x=\frac{25}{216} \\ =0.1157 \end{gathered}$

Hence the answer is 0.1157

(ii) None is defective becomes