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Dmitry [639]
4 years ago
14

Plz I need help’mmmmmmmm

Mathematics
1 answer:
Anna007 [38]4 years ago
6 0

Answer:

Therefore,

C=\pi d\\C\approx 3.14 \times d\\C\approx 43.96\ inches

Step-by-step explanation:

Let Assume Some Diameter of a Circle, to Solve it

Diameter = d = 14 inch ( say )

C =Circumference

Pi =constant = 3.14

To Find:

C = ?

Solution:

Formula for Circumference of a Circle is given as

C=\pi d

Where,

C = Circumference

d = Diameter

Now Substitute d = 14 inches we get

C=3.14\times 14\approx 43.96\ inches

This way we can find the circumference for any 'd' i.e Diameter

Therefore,

C\approx 43.96\ inches

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dimulka [17.4K]
The system of equations has one solution
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3 years ago
The triangle below is isosceles. Find the length of side xx in simplest radical form with a rational denominator.
coldgirl [10]

Answer:

Solution given:

Since the given triangle is isosceles and right angled triangle

perpendicular [p]=base[b]=x

hypotenuse [h]=6

we have

by using Pythagoras law

p²+b²=h²

x²+x²=6²

2x²=36

x²=36/2

x²=18

x=\sqrt{18}

<u>x</u>=\bold{3\sqrt{2}}

6 0
3 years ago
Emma collected 72 apples from the orchard and put an equal number of apples into 6 baskets. Mrs. Doolan wants 3 baskets of apple
stira [4]

Answer:

36 apples

Step-by-step explanation:

First, divide 72 by 6 to find out how many apples are in 1 basket.(Answer 12)

There will be 12 apples in one basket.

Mrs. Doolan wants 3 baskets so multiply 12 by 3 to get 36.

72/6= 12

12X3=<u>36</u>

7 0
3 years ago
Read 2 more answers
A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min
Dmitry [639]

At any time t (min), the volume of solution in the tank is

500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}

If A(t) is the amount of salt in the tank at any time t, then the solution has a concentration of \dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}.

The net rate of change of the amount of salt in the solution, A'(t), is the difference between the amount flowing in and the amount getting pumped out:

A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)

Dropping the units and simplifying, we get the linear ODE

A'=10+5\sin\dfrac t4-\dfrac A{10}

10A'+A=100+50\sin\dfrac t4

Multiplying both sides by e^{10t} allows us to identify the left side as a derivative of a product:

10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}

\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}

e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt

Integrate and divide both sides by e^{10t} to get

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}

The tanks starts off with 30 lb of salt, so A(0)=30 and we can solve for C to get a particular solution of

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}

6 0
3 years ago
PLS HELP ME 5x+3=7x-1
TiliK225 [7]

Answer:

Hello! the answer is X=2

Step-by-step explanation:

8 0
2 years ago
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