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vazorg [7]
3 years ago
10

What is the greatest common factor of 56, 80 and 56?

Mathematics
2 answers:
FrozenT [24]3 years ago
4 0
Answer: 8


I hope this helps and have a wonderful day filled with joy!!

<3
Irina-Kira [14]3 years ago
3 0
The greatest common factor would be 8
You might be interested in
Which is one way to check 102 ÷ 6 = 17
Bad White [126]
Hey, Imherkk!
You can check by using a calculator.
Another way is doing 17*6.
If you get 102(you do) then you're answer is right.
I hope this helps;)
8 0
3 years ago
Read 2 more answers
The area of a certain rectangle is 288 yd2. The perimeter is 68 yd. What are the dimensions of the rectangle?
arsen [322]

Answer:

The rectangle is 16*18

Step-by-step explanation:

The area of a rectangle is length * width and the perimeter is 2 times length * width

A = l*w

P = 2(l+w)

Replacing A and P

288 = l*w

68 = 2(l+w) => 34 = l+w => 34 - w = l

replacing l in the area

288 = (34 - w) w

w^2 - 34w + 288 = 0

(w - 16)(w - 18)

w = 16

w = 18

replacing in 34 - w = l

you get that when w = 16, l = 18 and when w = 18, l = 16

8 0
3 years ago
Do you tailgate the car in front of you? About 35% of all drivers will tailgate before passing, thinking they can make the car i
Vesna [10]

Answer:

(a) The histogram is shown below.

(b) E (X) = 4.2

(c) SD (X) = 2.73

Step-by-step explanation:

Let <em>X</em> = <em>r</em><em> </em>= a driver will tailgate the car in front of him before passing.

The probability that a driver will tailgate the car in front of him before passing is, P (X) = <em>p</em> = 0.35.

The sample selected is of size <em>n</em> = 12.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 12 and <em>p</em> = 0.35.

The probability function of a binomial random variable is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x}

(a)

For <em>X</em> = 0 the probability is:

P(X=0)={12\choose 0}(0.35)^{0}(1-0.35)^{12-0}=0.006

For <em>X</em> = 1 the probability is:

P(X=1)={12\choose 1}(0.35)^{1}(1-0.35)^{12-1}=0.037

For <em>X</em> = 2 the probability is:

P(X=2)={12\choose 2}(0.35)^{2}(1-0.35)^{12-2}=0.109

Similarly the remaining probabilities will be computed.

The probability distribution table is shown below.

The histogram is also shown below.

(b)

The expected value of a Binomial distribution is:

E(X)=np

The expected number of vehicles out of 12 that will tailgate is:

E(X)=np=12\times0.35=4.2

Thus, the expected number of vehicles out of 12 that will tailgate is 4.2.

(c)

The standard deviation of a Binomial distribution is:

SD(X)=np(1-p)

The standard deviation of vehicles out of 12 that will tailgate is:

SD(X)=np(1-p)=12\times0.35\times(1-0.35)=2.73\\

Thus, the standard deviation of vehicles out of 12 that will tailgate is 2.73.

4 0
3 years ago
Simplify and rationalize denominator<br>3√3x^5y^4÷8x​
vladimir1956 [14]

Answer:

15jnzks.sjnsjdkdksksk

4 0
3 years ago
Determine the quotient, q(x), and remainder, r(x) when
Vinvika [58]
ANSWER

Quotient:

q(x) = 4 {x}^{2} + 3x + 2

Remainder:

r(x) = 3x + 1

EXPLANATION

The given functions are

f(x) = 12 {x}^{4} + 21 {x}^{3} + 31 {x}^{2} + 21x + 9

and

g(x) = 3 {x}^{2} + 3x + 4

We want to find the remainder and quotient when f(x) is divided by g(x).

We perform the long division as shown in the attachment.

The quotient is

q(x) = 4 {x}^{2} + 3x + 2

The remainder is

r(x) = 3x + 1

5 0
3 years ago
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