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choli [55]
3 years ago
15

How do you write this number using digits?

Mathematics
1 answer:
jasenka [17]3 years ago
4 0
Answer: 506,827

Explanation: Google
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Five tickets to a play cost $38. What does each ticket cost if they all cost the same?
ra1l [238]

Answer:

this mah not be right but i believe it is 7.6

Step-by-step explanation:

if i did it correctly where you just divide 38 by 5 it should be 7.6

6 0
2 years ago
Draw a box plot for the following data. {35, 50, 50, 48, 48, 32, 38, 41, 48, 34, 29, 23, 41, 34, 43}
loris [4]

I can't really draw one, but the points would be, 23,34,41,48,50

7 0
3 years ago
Which degree of rotation is equivalent to a 270 degree clockwise rotation?
Dominik [7]
A 90 degree counter clockwise rotation
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2 years ago
"The fitted regression line will always run through the mean of the observed data. In other words, the point (x with bar on top,
Kamila [148]
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2 years ago
A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40
malfutka [58]
PART A

The given equation is

h(t) = - 16 {t}^{2} + 40t + 4

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4

We add and subtract

- 16(- \frac{5}{4} )^{2}

to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4

We again factor -16 out of the first two terms to get,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4

This implies that,

h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4

The quadratic trinomial above is a perfect square.

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4

This finally simplifies to,

h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29

The vertex of this function is

V( \frac{5}{4} ,29)

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

29

PART B

When the ball hits the ground,

h(t) = 0

This implies that,

- 16 ( t- \frac{5}{4}) ^{2} +29 = 0

We add -29 to both sides to get,

- 16 ( t- \frac{5}{4}) ^{2} = - 29

This implies that,

( t- \frac{5}{4}) ^{2} = \frac{29}{16}

t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }

t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}

t = \frac{ 5 + \sqrt{29} }{4} = 2.60

or

t = \frac{ 5 - \sqrt{29} }{4} = - 0.10

Since time cannot be negative, we discard the negative value and pick,

t = 2.60s
8 0
3 years ago
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