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3 years ago

What is negative 2 times nine

Mathematics

2 answers:

emmainna [20.7K]3 years ago

8 0

-18
try it on mentally or calcular hope its useful

MrMuchimi3 years ago

5 0

-18 because a negative number times positive is negative.
~JZ

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For every 3 presents lisa wrapped, helen wrapped 5. if they wrapped a total of 184 how many did each wrap. ( how did you get the

igor_vitrenko [27]

3 : 5.....thats ur ratio...added = 8...so basically, Lisa wrapped 3 out of 8 (or 3/8) and Helen wrapped 5 out of 8 (or 5/8)

3/8(184) = 552/8 = 69 : Lisa wrapped 69
5/8(184) = 920/8 = 115 : Helen wrapped 115

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3 years ago

Write three different sentences that could describe the relationship between the quantities $27, $81

Olenka [21]

1) 27+x=81
2)27+81=108
3)81-x=27

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3 years ago

What is the sum of the measures of the interior angles of a pentagon and 10-gon (decagon)?

Arada [10]

Answer:

540

Step-by-step explanation:

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3 years ago

Read 2 more answers

Given h(x) = 3x + 4, find h(-1).

larisa86 [58]

Plug in -1 for x
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Solution: h(-1) = 1

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3 years ago

What is a solution to the equation 3 / m + 3 - M / 3 - M equals m^2 + 9 / m^2-9?

Mnenie [13.5K]

Answer: Last option.

Step-by-step explanation:

Given the equation:

$\frac{3}{m+3}-\frac{m}{3-m}=\frac{m^2+9}{m^2-9}$

Follow these steps to solve it:

- Subtract the fractions on the left side of the equation:

$\frac{3(3-m)-m(m+3)}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{9-3m-m^2-3m}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}\\\\\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{m^2-9}$

- Using the Difference of squares formula ( $a^2-b^2=(a+b)(a-b)$ ) we can simplify the denominator of the right side of the equation:

$\frac{-m^2-6m+9}{(m+3)(3-m)}=\frac{m^2+9}{(m+3)(m-3)}$

- Multiply both sides of the equation by $(m+3)(3-m)$ and simplify:

$\frac{(-m^2-6m+9)(m+3)(3-m)}{(m+3)(3-m)}=\frac{(m^2+9)(m+3)(3-m)}{(m+3)(m-3)}\\\\-m^2-6m+9=\frac{(m^2+9)(3-m)}{(m-3)}$

- Multiply both sides by $m-3$ :

$(-m^2-6m+9)(m-3)=\frac{(m^2+9)(3-m)(m-3)}{(m-3)}\\\\(-m^2-6m+9)(m-3)=(m^2+9)(3-m)$

- Apply Distributive property and simplify:

$(-m^2-6m+9)(m-3)=(m^2+9)(3-m)\\\\-m^3-6m^2+9m+3m^2+18m-27=3m^2+27-m^3-9m\\\\-m^3-3m^2+27m-27+m^3-3m^2+9m-27=0\\\\-6m^2+36m-54=0$

- Divide both sides of the equation by -6:

$\frac{-6m^2+36m-54}{-6}=\frac{0}{-6}\\\\m^2-6m+9=0$

- Factor the equation and solve for "m":

$(m-3)^2=0\\\\m=3$

In order to verify it, you must substitute $m=3$ into the equation and solve it:

$\frac{3}{3+3}-\frac{3}{3-3}=\frac{3^2+9}{3^2-9}\\\\\frac{3}{6}-\frac{3}{0}=\frac{18}{0}$

<em>NO SOLUTION</em>

7 0

3 years ago