Answer:
X=11
Step-by-step explanation:
X=11 because u Solve for the first variable in one of the equations, then substitute the result into the other equation.
Answer:
d + n = 147
0.10d + 0.05n = 11.65
d = 86, n = 61
Step-by-step explanation:
Let
Number of dimes = d
Number of nickels = n
Total coins = 147
Total value = $11.65
d + n = 147 (1)
0.10d + 0.05n = 11.65 (2)
From (1)
d = 147 - n
Substitute d = 147 - n into
0.10d + 0.05n = 11.65
0.10(147 - n) + 0.05n = 11.65
14.7 - 0.10n + 0.05n = 11.65
- 0.10n + 0.05n = 11.65 - 14.7
-0.05n = -3.05
n = -3.05 / -0.05
= 61
n = 61
Substitute n = 61 into
d + n = 147
d + 61 = 147
d = 147 - 61
d = 86
Answer:
P=0.147
Step-by-step explanation:
As we know 80% of the trucks have good brakes. That means that probability the 1 randomly selected truck has good brakes is P(good brakes)=0.8 . So the probability that 1 randomly selected truck has bad brakes Q(bad brakes)=1-0.8-0.2
We have to find the probability, that at least 9 trucks from 16 have good brakes, however fewer than 12 trucks from 16 have good brakes. That actually means the the number of trucks with good brakes has to be 9, 10 or 11 trucks from 16.
We have to find the probability of each event (9, 10 or 11 trucks from 16 will pass the inspection) . To find the required probability 3 mentioned probabilitie have to be summarized.
So P(9/16 )= C16 9 * P(good brakes)^9*Q(bad brakes)^7
P(9/16 )= 16!/9!/7!*0.8^9*0.2^7= 11*13*5*16*0.8^9*0.2^7=approx 0.02
P(10/16)=16!/10!/6!*0.8^10*0.2^6=11*13*7*0.8^10*0.2^6=approx 0.007
P(11/16)=16!/11!/5!*0.8^11*0.2^5=13*21*16*0.8^11*0.2^5=approx 0.12
P(9≤x<12)=P(9/16)+P(10/16)+P(11/16)=0.02+0.007+0.12=0.147
Answer:
(d-5)
Step-by-step explanation:
we know that
The phrase"five fewer than d days" is equal to subtract 5 from the number d
so
d minus 5-----> (d-5)
