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4 years ago

What is the greatest common factor of 19x^7 and 3x^5

1 answer:

6 0

Hi the answer is x^5.
19 is a prime number, so 3 cannot be a factor. However, bother terms contain x^5, this is the greatest common factor.

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Imagine we are throwing a five-sided die 50 times. On average, out of these 50 throws how many times would this five-sided die s

Mars2501 [29]

Answer:

$30$

Step-by-step explanation:

There are 3 outcomes out of 5 that are odd.

$\frac{3}{5}$

Throw it 50 times.

$50*\frac{3}{5}$

4 0

3 years ago

Read 2 more answers

Donna guessed there were 400 jellybeans in a jar. There were really 480 jellybeans. What was her percent of error?

miss Akunina [59]

Answer:

≈83.33%

Step-by-step explanation:

400/480 = 5/6

56 * 100 = ≈83.33%

4 0

3 years ago

at East Middle School there 58 left hand students in 609 right-handed students the numbers of left and right handed students at

snow_tiger [21]

the answer is 504 because 609/58 is 10.5 and then multiply 48 times 10.5 and you get 504

7 0

3 years ago

Read 2 more answers

Gladys classifies the following system of equations.

netineya [11]

The system is inconsistent because the slopes are the same and the lines are different.

A linear equation is of the form:

y = mx + b

where y, x are variables, m is the slope of the line and b is the y intercept.

Given the following system of equations:

y = 6x + 2 (1)

y = 6x + 1 (2)

We can see that both equations have the same slope of 6 but have different y intercepts.

Hence the system is inconsistent because the slopes are the same and the lines are different.

Find out more at: brainly.com/question/13911928

5 0

3 years ago

A boat traveled 153 miles downstream and back. The trip downstream took 9 hours. The trip back took 17 hours. What is the speed

fgiga [73]

Speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

<h3><u><em>Solution:</em></u></h3>

Let s = the speed of the boat in still water in miles/hour

Let c = the speed of the current in miles/hour

<em><u>Formula to remember:</u></em>

If the speed of a boat in still water is s miles/hr and the speed of the current is c miles/hr, then:

Speed downstream = (s + c) miles per hour

Speed upstream = (s - c) miles per hour

<em><u>Given:</u></em>

boat traveled 153 miles downstream and back

distance for downstream = 153 miles

distance for upstream = 153 miles

time taken for downstream = 9 hours

Time taken for upstream = 17 hours

<em><u>The relation between speed, distance and time is given as:</u></em>

$distance = speed \times time$

<em><u>For downstream:</u></em>

$153 = (s + c) \times 9$

$s + c = \frac{153}{9} = 17$

s + c = 17 ------- eqn 1

<em><u>For upstream:</u></em>

$153 = (s - c) \times 17\\\\s - c = \frac{153}{17} = 9$

s - c = 9 ------- eqn 2

<em><u>Let us solve eqn 1 and eqn 2 to find values of "s" and "c"</u></em>

Add eqn 1 and eqn 2

s + c = 17

s - c = 9

(+) -------------

2s = 26

Substitute s = 13 in eqn 1

13 + c = 17

c = 17 - 13 = 4

Thus the speed of boat in still water is 13 miles per hour and speed of current is 4 miles per hour

8 0

3 years ago