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ss7ja [257]
3 years ago
13

Imagine we are throwing a five-sided die 50 times. On average, out of these 50 throws how many times would this five-sided die s

how an odd number (1, 3 or 5)?​
Mathematics
2 answers:
Mars2501 [29]3 years ago
4 0

Answer:

30

Step-by-step explanation:

There are 3 outcomes out of 5 that are odd.

\frac{3}{5}

Throw it 50 times.

50*\frac{3}{5}

Lynna [10]3 years ago
4 0

Answer:

30.

Step-by-step explanation:

The probability of throwing a 1, 3 or 5 on one throw is 3/5.

So on 50 throws the average would be  50 * 3/5 = 30 times.

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92% of 3.9 =<br> pls answer
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Answer:

35.88


Step-by-step explanation:

92/100 = x/39. 100x = 3588. x = 35.88

6 0
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A parallelogram's area is given by the expression 4x2 + 2x + 6. The height of the parallelogram is 2x2. what is the base of the
yawa3891 [41]
A = B × h
A = 4x^2 + 2x + 6
h = 2x^2
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B = (2x^2 + x + 3)/x^2
7 0
4 years ago
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What is the explicit formula of -1,-3,-9,-27
TEA [102]

Answer:

(-1)* (3)^(n-1)

Step-by-step explanation:

common ratio is 3 and the first term is -1

the explicit formula is a * r^ ( n-1)

i.e., (-1) * 3^(n-1)

3 0
4 years ago
How many 3/4s are in 15?
jasenka [17]

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7 0
3 years ago
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Maria studied the traffic trends in India. She found that the number of cars on the road increases by 10% each year. If there we
alekssr [168]

Answer: 8,800,000

Step-by-step explanation:

First year recorded number of cars on the roads   = 80, 000,000

Increase rate                                                              = 10%

In the second year , the number of cars recorded  = 10% of 80,000,000

                                                                                    = 10/100 x 80,000,000

                                                                                    = 8,000,000

                                                                                =  80,000,000 + 8,000,000

                                                                                    = 88,000,000

In the third year, the number of cars recorded       = 10% of 88,000,000

                                                                                   = 10/100 x 88,000,000

                                                                                   = 8,800,000

                                                                                  = 88,000,000 + 8,800,000

                                                                                  = 96,800,000.

The number of cars we had  more in the third years compared to year two will be

                                                                                = 96,800,000 - 88,000,000

                                                                                = 8,800,000

           

6 0
4 years ago
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