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Sladkaya [172]
3 years ago
13

Simplify -2w < -16 I am stuck on this question can someone help me please?

Mathematics
2 answers:
sergejj [24]3 years ago
8 0
-2w < -16

isolate the w
Note: you change the sign only when you DIVIDE A NEGATIVE

-2w/-2 < -16/-2

w > 8

w > 8 is your answer

hope this helps 
MrMuchimi3 years ago
8 0
Okay, you need to divide -2 into both sides.

Remember, when you divide by a negative you flip the signs.

w>8

I hope this helps!
~cupcake
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Help! plz and thx! what is 4:08 - 1:15 = ?:? plz, help WITH AND WITHOUT REGROUPING thx!!!!!!! I will give u the brainiest! plz a
sergejj [24]

Answer:

2:53

Step-by-step explanation:

I believe that you are subtracting times here, so have in mind that if the first number indicates hours, and the second number minutes, and you are asked to subtract more of one quantity (minutes for example) than what you have, you will need to convert some of the hours into minutes.

Recall that 1 hour equals 60 minutes.

in the difference   4:08 minus 1:15, you sre expected to subtract minutes from minutes and hours from hours. Now the number of minutes you need to subtract from 08 is 15 (larger than 08) so we need to convert 1 hour into minutes in the first expression, and then (with enough minutes to deal with), we can subtract:

4:08 is the same as 3:68 where we converted 1 hour to 60 minutes and added those 60 minutes to the existing 8 .

Now the difference can be performed:

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6 0
3 years ago
Because of their connection with secant​ lines, tangents, and instantaneous​ rates, limits of the form ModifyingBelow lim With h
Gre4nikov [31]

Answer:

\dfrac{1}{2\sqrt{x}}

Step-by-step explanation:

f(x) = \sqrt{x} = x^{\frac{1}{2}}

f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}

We use binomial expansion for (x+h)^{\frac{1}{2}}

This can be rewritten as

[x(1+\dfrac{h}{x})]^{\frac{1}{2}}

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}

From the expansion

(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots

Setting x=\dfrac{h}{x} and n=\frac{1}{2},

(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots

=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots

Multiplying by x^{\frac{1}{2}},

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots

\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots

The limit of this as h\to 0 is

\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}} (since all the other terms involve h and vanish to 0.)

8 0
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