The first one I'll go with 2nd one ...But I'm dumb so hope that helps
D. drawing a vertical line x = 3 cuts the figure in symmetrical shape therefore equation for line of symmetry should be
x =3
Hey there!
To solve the first problem, I've found it easiest to solve the equation for, say, values –2 through +2 and create a table of values for you to begin graphing this function. You may need to do more depending on the equation itself.
Some points are: (–2, 0.75), (–1, 1.5), (0, 3), (1, 6) and (2, 12). You can check which graph matches up with these points the closest to get your answer of D.
To solve the second problem, you'll need to use the distance equation.
x1 = –4, y1 = 3
x2 = –1, y2 = 1
___________________
√ (x2–x1)^2 + (y2–y1)^2
_________________
√ (–1–(–4)^2 + (1–3)^2
_______________
√ (–1+4)^2 + (–2)^2
____________
√ (3)^2 + (–2)^2
_____
√ 9 + 4
___
√ 13, making your answer D
For your third question, I always just counted the number of units the point was from the line of reflection. You'll count twice diagonally towards the line from point C for this one, staying on the "crosshairs" of the graph. All you need to do then is count two diagonal units along the same line, then you'll get your answer of (2, 6), or D.
For your final question, A and B are immediately out, since they won't be parallel to the 4x equation. You'll need to solve both of your remaining equations for y with 2 plugged in for x; whichever one equals 7 will be your answer. In this case, it will be D.
Hope this helped you out! :-)
The probability of an event is expressed as
Given:
The probability of drwing two blue balls one after the other is expressed as
For the first draw:
For the second draw, we have only 1 blue ball left out of a total of 6 balls (since a blue ball with drawn earlier).
Thus,
The probability of drawing two blue balls one after the other is evaluted as
The probablity that none of the balls drawn is blue is evaluted as
Hence, the probablity that none of the balls drawn is blue is evaluted as
