The period of the function is that distance where the function becomes equal again.
We have then:
Part 1:
The period of the function is:
T = 3
Part 2:
The period of the function is:
T = 4
Answer:
The period of functions 1 and 2 respectively are:
T = 3
T = 4
U need to work it out and solve it. To find the answer
Answer:
Step-by-step explanation:
8z (3x^2 +y)
An 8th-degree polynomial needs 9 terms that involve
x⁸, x⁷, ..., x¹, and x⁰.
x=10 implies that (x-10) is a factor of the polynomial according to the Remainder theorem.
Let the polynomial be of the form
f(x) = a₁x⁸ + a₂x⁷ + a₃x⁶ +a₄x⁵ + a₅x⁴ + a₆x³ + a₇x² + a₈x + a₉
The first few lines of the synthetic division are
10 | a₁ a₂ a₃ a₄ a₅ a₆ a₇ a₈ a₉ ( the first row has 9 coefficients)
-----------------------------------------
a₁
Answer:
The first row has 9 coefficients.
Answer:
(0,-1)
(1,-5)
(2,-9)
Step-by-step explanation:
y = −4x −1
Let x=0
y = 0-1 = -1 (0,-1)
Let x = 1
y = -4(1) -1 = -4-1 =-5 (1,-5)
Let x = 2
y = -4(2) -1 = -8-1 =-9 (2,-9)
