Question

Please help. What is the equation of the line in slope-intercept form?​

Answer 1

Answer:

Ray, you need the slope-intercept formula  y=mx+b

Step-by-step explanation:

Next you'll need 2 points,  any points are fine.  Just find two easy ones along the line.  I'll just pick  Point 1  as P1 = ( 0,4)  and point 2 as P2 = (4,0) because they are easy to work with.

next use

point P1 (0,4)  in the form (x1,y1)

point P2(4,0)  in the form (x2,y2)

slope = m

m = (y2-y1) / (x2-x1)

m = (0-4) / (4-0)

m = -4 / 4

m = -1

now use the point slope with one of the points,  to find the slope-intercept form.

y - y1 = m(x -x1)

y - 4 =  -1(x-0)

y -4 = -x

y = -x + 4

note:

y = mx +b

y = (-1)x + b    is the form.   see?

Answer 2

Answer:

y = mx + b

m = slope

b = intercept

From the graphic:

(x₁, y₁) = (0, 4)

(x₂, y₂) = (4, 0)

$\frac{y-y_{1} }{y_{2} -y_{1} } =\frac{x-x_{1} }{x_{2} -x_{1} } \\\\\frac{y-4 }{0 -4} =\frac{x-0 }{4 -0 } \\\\\frac{y-4}{-4} =\frac{x}{4} \\\\(y-4)4=-4x\\\\y-4=-x\\y=-x+4$