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il63 [147K]
3 years ago
9

the ratios of the measure sides of a triangle is 4:10:7. find the length of each side if the perimeter of the triangle is 252 me

ters
Mathematics
1 answer:
mash [69]3 years ago
6 0

Answer:

Step-by-step explanation:

perimeter = 252

4:10:7 = 4 + 10 + 7 =21

10* 252/21 = 120

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93.5 \times 12.75  = 1192.125 \times 6 = 7152.75
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3 years ago
If f(x) = x^2 – 25 and g(x) = x – 5, what is the domain of (f/g)(x)
daser333 [38]
(f/g)(x) = (x^2-25)/(x-5) = x+5. So domain will be R, all real numbers
4 0
3 years ago
Read 2 more answers
What is the surface area of prism below?
valkas [14]

Answer:

240 cm^2

Step-by-step explanation:

Comment

There are 2 ends that are in the shape of a triangle

There is 1 base that is rectangular

There are 2 roof tops that are rectangular in shape.

Find the area of the triangles, base, 2 roof parts.

Solution

<em>1 base</em>

w = 4 cm

L = 12 cm

Area = L*w

Area = 12*4

Area =                                             48 cm^2

<em>Two Triangles</em>

B = 4 cm

H = 6 cm

Area = 1/2 b * h

Area = 1/2 6 * 4

Area = 12 cm

But there are 2 triangles

Area 2 triangles                              24 cm^2

<em>Two roof tops</em>

L = 12 cm

w = 7 cm          

Area = L*w for one roof top        

Area = 12*7 cm                                

Area = 84 cm^2

But there are 2 of them      <u>            168 cm^</u>2

Total Area                                        240  cm^2

6 0
2 years ago
Read 2 more answers
Y=4, -4y + 5 evaluate it please​
bearhunter [10]

Answer: 11

Step-by-step explanation:

-4×4= - 16

-16+5= 11

3 0
3 years ago
Determine the probability of selecting a two-child family with one boy and one girl assuming boys and girls are equally likely
Fittoniya [83]

Using the binomial distribution, it is found that there is a 0.5 = 50% probability of selecting a two-child family with one boy and one girl.

For each child, there are only two possible outcomes, either it is a boy, or it is a girl. The probability of a child being a boy or being a girl is independent of any other child, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • Two children, hence n = 2.
  • Equally as likely to be a boy or a girl, hence p = 0.5.

The probability of one of each is P(X = 1), hence:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.5)^{1}.(0.5)^{1} = 0.5

0.5 = 50% probability of selecting a two-child family with one boy and one girl.

A similar problem is given at brainly.com/question/24863377

3 0
3 years ago
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