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Aleks [24]
4 years ago
11

Estimate the quotient 63.5 dividend by 5

Mathematics
1 answer:
Gala2k [10]4 years ago
3 0
12.70 or rounded 13 yeeeeeeeeee boiiiiiiiiiiii
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How do you do this please help ?
Vladimir79 [104]

Answer:

Area: A = 42x - 49

Step-by-step explanation:

Area of rectangle =  L * W

Plug in

A = 7 * (6x - 7)

A = 42x - 49

7 0
4 years ago
One fish is 4 feet below sea level. Another fish is 3 feet below sea level. Write each position as an integer. Which integer is
Vlad1618 [11]

Answer:

fish a has a great interest

5 0
3 years ago
Read 2 more answers
A line has equation y= −2/3 x-4.Write down the y-intercept of the line.
amid [387]
-2/3 is your y-internet
3 0
3 years ago
Answer along with how you got the answer <br> 3/8 + 1/8 + 2/8 = ?
zzz [600]

Answer:

6/8 simplified form 3/4

Step-by-step explanation:

Given: 3/8 + 1/8 + 2/8

Here we have to find the sum of the fractions.

All the fractions are like fractions.

So we can add the numerators and keep the denominator as it is. (We should not add the denominator)

Therefore,

3/8 + 1/8 + 2/8 = (3 + 1 + 2)/8

= 6/8

We can simplify this fraction by dividing both the numerator and the denominator by 2.

= 6/8

= 3/4

Hope this is will help you to understand the concept.

Thank you.

3 0
4 years ago
Sam attempts a 42-yard field goal in a football game. For his attempt to be a success, the football needs to pass through the up
Zigmanuir [339]

Answer:

The correct option is;

The kick is good! The ball clears the crossbar by nearly 15 feet.

Step-by-step explanation:

Here we have;

Velocity of ball = 70 ft/s

Angle of motion = 50°

Therefore;

Vertical component of velocity, v_y = v×sinθ = v×sin×50 = 53.62 ft/s

v_y = u_y - g·t

At maximum height v_y = 0, therefore;

u_y = g·t and

t =  u_y/g

Where:

u_y = Initial vertical velocity = 53.62 ft/s

g = Acceleration due to gravity = 32.1740 ft/s²

∴ t = 53.62/32.1740 = 1.66666 s

Total time of flight = 2 × 1.66666 = 3.33332 s

Max height is given by the following relation;

v_y² = u_y² - 2·g·s

v_y = 0 ft/s at maximum height, therefore;

u_y² = 2·g·s

53.62² = 2×32.1740×s

s = 53.62² ÷(2×32.1740) = 44.69 ft

Horizontal velocity = 70×cos(50) = 44.995 ft/s

Hence the time it takes the ball to reach 42 yards is given by the following relation;

42 yards = 126 ft

Time, t = \frac{Distance}{Velocity} = \frac{126}{44.995} = 2.8 \, s

Height of ball at 2.8 s is given by;

Direction of ball at 2.8 s = downwards

Hence time  after peak = 2.8 - 1.666 = 1.1336429 s

Position at 2.8 s is given by

s = u_y ·t + 1/2·g·t²

u_y = 0 ft/s as ball is on second half of flight

∴ s = 1/2·g·t² = 1/2×32.1740×1.1336429²= 20.674 ft below maximum height

∴ Height above ground =  Maximum height - 20.674 ft = 44.69 - 20.674

Height above ground = 24.01 ft

Hence the ball clears the crossbar by 24.01 - 10 = 14.01 ft

The best option is therefore;

The kick is good! The ball clears the crossbar by nearly 15 feet.

8 0
4 years ago
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