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Lostsunrise [7]
4 years ago
12

A large population of laboratory animals has been allowed to breed randomly for a number of generations. After several generatio

ns, 25% of the animals display a recessive trait (aa), the same percentage as at the beginning of the breeding program. The rest of the animals show the dominant phenotype, with heterozygotes indistinguishable from the homozygous dominants.
What is the most reasonable conclusion that can be drawn from the fact that the frequency of the recessive trait (aa) has not changed over time?

a) The population is undergoing genetic drift.
b) The two phenotypes are about equally adaptive under laboratory conditions.
c) The genotype AA is lethal.
d) There has been a high rate of mutation of allele A to allele a.
e) There has been sexual selection favoring allele a.
Biology
1 answer:
vesna_86 [32]4 years ago
4 0

Answer:

b) The two phenotypes are about equally adaptive under laboratory conditions.

Explanation:

According to the given information, the frequency of homozygous recessive genotype and the recessive allele is not changed over generations and is maintained at a constant level. A population maintains allele frequencies over generations without any changes when the environment is not changing and the existing allele frequencies are beneficial in terms of survival and reproductive success of the individuals.

In the given breeding program, both the recessive and dominant genotypes should impart beneficial adaptive traits to the organisms resulting in no change in their frequencies over several generations.

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Answer:

The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%

Explanation:

You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:

Cross) AAbbCcDDEeff     x      AaBBCcddEEFF

Cross For each gene by separately:

  • Parental )        AA    x    Aa

       Gametes)  A    A         A    a

        F1)             2/4 AA  

                          2/4 Aa

  • Parental )        bb    x    BB

         Gametes)  b    b         B   b

          F1)                   4/4 Bb

  • Parental )        Cc    x    Cc

        Gametes)  C    c         C    c

         F1)             1/4 CC

                           2/4 Cc

                            1/4 cc

  • Parental )        DD    x    dd

       Gametes)  D    D          d    d

        F1)             4/4 Dd

  • Parental )        Ee    x    EE

        Gametes)     E     e      E     E

         F1)             2/4 Ee

                           2/4 EE

  • Parental )        ff    x    FF

         Gametes)     f     f      F     F

          F1)             4/4 Ff

So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:

4/4 A-  x  4/4 Bb   x   1/4 cc   x   4/4 Dd   x  4/4 E-   x   4/4 Ff =  

1024/4096 = 0.25 A-BbccDdE-Ff =25%  

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