Answer:
The fraction of the offspring that will show the phenotype produced by the recessive c allele is 1024/4096 = 0.25 A-BbccDdE-Ff = 25%
Explanation:
You can calculate the fraction of the offspring that will show the phenotype produced by the recessive c allele by making the punnet square for each gene and then multipling the phenotypic proportions, like this:
Cross) AAbbCcDDEeff x AaBBCcddEEFF
Cross For each gene by separately:
Gametes) A A A a
F1) 2/4 AA
2/4 Aa
Gametes) b b B b
F1) 4/4 Bb
Gametes) C c C c
F1) 1/4 CC
2/4 Cc
1/4 cc
Gametes) D D d d
F1) 4/4 Dd
Gametes) E e E E
F1) 2/4 Ee
2/4 EE
Gametes) f f F F
F1) 4/4 Ff
So, fraction of the offspring that will show the phenotype produced by the recessive c allele is:
4/4 A- x 4/4 Bb x 1/4 cc x 4/4 Dd x 4/4 E- x 4/4 Ff =
1024/4096 = 0.25 A-BbccDdE-Ff =25%
Answer :The Cu ion is the metal.
• The copper (II) ion is the Cation
• The two chloride ions are the Anions
Explanation:
Chordates, or members of phylum Chordata, possess a backbone.
Endangered Species Act of 1973
Answer:
1) By 11:30pm
2) Shortly before midnight (few minutes to 12:00am)
Explanation:
Since the strain of bacteria takes 1 minute to divide (double its population), and by midnight (12:00am) the entire bottle becomes full, then:
I) Subtract Initial division time from Final division time i.e 12:00 - 11:00 = 1 hour
II) Split 1 hour into two (60minutes makes 1 hour)
I hour/2 = 30 minutes
Definitely, the bottle will be half filled by 11:30pm
2) Once half filled, the rapidly dividing cells reach for the top of the bottle as midnight approaches. By 11:50pm upwards, bottle space must have been running out