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Rainbow [258]
3 years ago
11

what is the difference between the greatest and least amount of juice? could you please tell me how to do it

Mathematics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

More juice.

Step-by-step explanation:

The difference between the greatest and least amount of juice is that there is more juice in one cup. If this is not the answer you were looking for, please let me know, and I am sorry for the inconvienience.

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A painter leans a 12-foot ladder against a house. The base of the ladder is
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11.3 feet.

12 squared (144) minus 4 squared (16) is equal to 128. The square root of 128 is approximately 11.3.

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Find the length of the missing side. the triangle not drawn to scale. (Image attached)
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Answer: 8

Step-by-step explanation:

 The triangle shown in the image attached is a right triangle.

Therefore, to calculate the missing lenght of the triangle you can apply the Pythagorean Theorem, which is shown below:

a^2=b^2+c^2

Where <em>a</em> is the hypotenuse and <em>b</em> and <em>c</em> are the legs.

The problem gives you the value of the hypotenuse and the value of one leg. Therefore, you must solve for the other leg from a^2=b^2+c^2, as following:

17^2=15^2+c^2\\c=\sqrt{17^2-15^2}\\c=8

Therefore, the lenght of the missing side is: 8

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3 years ago
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What is the area of the sector bound by the center of the circle and arc CD in the circle below? Circle A is shown with a radius
kotykmax [81]
Area = 45/360 (pi)(15)^2
88.31
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Solve by elimination <br> 5x-y=12 <br> 3x+2y=2
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(2)5x-y=12
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write a polynomial function of least degree with integral coefficients that has the given zeros. -(1/3), -i
inessss [21]

Answer:

f(x)=3x^3+x^2+3x+1

Step-by-step explanation:

If a real number -\frac{1}{3} is a zero of polynomial function, then

x-\left(-\dfrac{1}{3}\right)=x+\dfrac{1}{3}

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If a complex number -i is a xero of the polynomial function, then the complex number i is also a zero of this function and

x-(-i)=x+i\ \text{ and }\ x-i

are two factors of this function.

So, the function of least degree is

f(x)=\left(x+\dfrac{1}{3}\right)(x+i)(x-i)=\left(x+\dfrac{1}{3}\right)(x^2-i^2)=\\ \\ =\left(x+\dfrac{1}{3}\right)(x^2+1)=\dfrac{1}{3}(3x+1)(x^2+1)=\dfrac{1}{3}(3x^3+x^2+3x+1)

If the polynomial function must be with integer coefficients, then it has a form

f(x)=3x^3+x^2+3x+1

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3 years ago
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