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3 years ago

PT=3x+7 TQ=8x-8 answer asap please

1 answer:

3 0

Let’s suppose PT is equal to TQ
Therefore the equations will be equal
3x+7=8x-8
3x-8x=-7-8
-5x=-15
x=3
We have found x now we will substitute it into each equation
PT=3(3)+7
PT=9+7
PT=16
Then we will substitute the second equation
TQ=8(3)-8
TQ=24-8
TQ=16
And here is the answer please correct me if I’m wrong

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The wholesale cost of a bicycle is $98.75.

mixer [17]

Answer:

$131.60

Step-by-step explanation:

For the promotion, markup is 33.3% of the selling price.

Now, Selling Price = Cost price + Cost price*Markup

Selling Price = $98.75 + $98.75*33.3%

Selling Price = $98.75 + $32.88375

Selling Price = $131.63375

Selling Price = $131.60

Thus, the selling price of the bicycle after calculating the markup is $131.60.

8 0

3 years ago

A student receives his grade report from a local community college, but the GPA is smudged. He took the following classes: a 2 h

Olin [163]

Answer:

C. 3.0

Step-by-step explanation:

Lets calculate the points:

Art - 2 hrs - B (3) ⇒ 2*3 = 6 points
History - 3 hrs - A (4) ⇒ 3*4 = 12 points
Science - 4 hrs - C (2) ⇒ 4*2 = 8 points
Math - 3 hrs - B (3) ⇒ 3*3 = 9 points
Lab - 1 hr - A (4) ⇒ 1*4 = 4 points

Totals

Total hours = 13
Total points = 39

GPA = total points/ total hours

GPA = 39/13 = 3.0

Correct option is C

3 0

3 years ago

DIscrete Math

Daniel [21]

Answer:

Step-by-step explanation:

As the statement is ‘‘if and only if’’ we need to prove two implications

$f : X \rightarrow Y$ is surjective implies there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ .
If there exists a function $h : Y \rightarrow X$ such that $f\circ h = 1_Y$ , then $f : X \rightarrow Y$ is surjective

Let us start by the first implication.

Our hypothesis is that the function $f : X \rightarrow Y$ is surjective. From this we know that for every $y\in Y$ there exist, at least, one $x\in X$ such that $y=f(x)$ .

Now, define the sets $X_y = \{x\in X: y=f(x)\}$ . Notice that the set $X_y$ is the pre-image of the element $y$ . Also, from the fact that $f$ is a function we deduce that $X_{y_1}\cap X_{y_2}=\emptyset$ , and because $f$ the sets $X_y$ are no empty.

From each set $X_y$ choose only one element $x_y$ , and notice that $f(x_y)=y$ .

So, we can define the function $h:Y\rightarrow X$ as $h(y)=x_y$ . It is no difficult to conclude that $f\circ h(y) = f(x_y)=y$ . With this we have that $f\circ h=1_Y$ , and the prove is complete.

Now, let us prove the second implication.

We have that there exists a function $h:Y\rightarrow X$ such that $f\circ h=1_Y$ .

Take an element $y\in Y$ , then $f\circ h(y)=y$ . Now, write $x=h(y)$ and notice that $x\in X$ . Also, with this we have that $f(x)=y$ .

So, for every element $y\in Y$ we have found that an element $x\in X$ (recall that $x=h(y)$ ) such that $y=f(x)$ , which is equivalent to the fact that $f$ is surjective. Therefore, the prove is complete.

3 0

3 years ago

Rosalie earns extra money by working as a babysitter over the weekend. She charges $10 to drive to the home and an additional $8

agasfer [191]

Answer: The input values are B-number of hours (x).

The output values are C-charge for babysitting(y).

The value of $10 represents the B-y intercept.

The value of $8 represents the C-slope.

Step-by-step explanation:

Charges to drive to the home= $10

Additional charges per hour=$8

Let x be the hour she worked (independent variable) and y be the total charge for baby sitting (dependent variable)

Thus, the input values are number of hours (x) and the output values are charge for babysitting(y)

According to the situation the equation would be

y=8x+10

which is equivalent to the slope intercept form y=mx+c, where

m=8, slope of line

At x=0, y=10

Thus, $10 represents the y intercept

6 0

3 years ago

Read 2 more answers

Find the gradient of the line passing through (6,8) and (4,10)

Mariulka [41]

Question:

Find the gradient of the line passing through (6,8) and (4,10).

Answer:

-1 is the right answer.

Step-by-step explanation:

Slope of the line = The gradient of the line

Gradient of the line is known as change in the value of y-axis by change in the value of x-axis

Gradient = ∆y\∆x

$Gradient = \frac{y_ 2 - y_1}{x_2 - x_1} = \frac{(10 - 8)}{(4 - 6)} = \frac{(2)}{(- 2)} =\boxed{- 1}\\$

7 0

3 years ago