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eduard
3 years ago
9

Use the diagram to complete this proportion.​

Mathematics
1 answer:
Stolb23 [73]3 years ago
8 0

Answer:

LT

Step-by-step explanation:

This is not 100% but I think this is the answer

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Can someone help me with this answer I’m on a test and it’s almost due
Brrunno [24]

16.5 / p = 11 / 18

p = 16.5 × 18 / 11

p = ( 16.5 / 11 ) × 18

p = 1.5 × 18

p = 27

6 0
3 years ago
What is the ​ IQR ​ for the data set? {61, 70, 59, 55, 69, 59, 62} Drag and drop the correct answer into the box.
True [87]

Answer:

10

Step-by-step explanation:

Interquartile Range Formula:

IQR = Q3 - Q1

Quartiles Quartiles:

Q1 --> 59

Q2 --> 61

Q3 --> 69

69 - 59 = 10

[RevyBreeze]

5 0
2 years ago
Read 2 more answers
A car travels 192 miles using 6 gallons of gas At that rate how far can the car travel using 48 gallons of gas
Helen [10]

Answer: 1536 miles

Step-by-step explanation:

Use proportion to solve problem:

192:6=x:48

192*48=6x

x=192*48/6

x=192*8

X=1536 miles

4 0
4 years ago
Find the equation of the line through point (2,2) and parallel to y=x+4. Use a forward slash (i.e.”/“) for fractions (e.g. 1/2 f
aleksandr82 [10.1K]

Answer:

The equation of the line is, y = x

Step-by-step explanation:

The constraints of the required linear equation are;

The point through which the line passes = (2, 2)

The line to which the required line is parallel = y = x + 4

Two lines are parallel if they have the same slope, therefore, we have;

The slope of the line, y = x + 4 is m = 1

Therefore, the slope of the required line = 1

The equation of the required lime in point and slope form becomes;

y - 2 = 1 × (x - 2)

∴ y = x - 2 + 2 = x

The equation of the required line is therefore, y = x

5 0
4 years ago
Rationalise the following: <br> (Root3-1) / (root3+1)
Thepotemich [5.8K]

Answer:

2-\sqrt{3}

Step-by-step explanation:

\begin{aligned}\dfrac{\sqrt{3}-1}{\sqrt{3}+1}\times \dfrac{\sqrt{3}-1}{\sqrt{3}-1} &=\dfrac{(\sqrt{3}-1)(\sqrt{3}-1)}{(\sqrt{3}+1)(\sqrt{3}-1)}\\\\ & =\dfrac{\sqrt{3}\sqrt{3}-\sqrt{3}-\sqrt{3}+1}{\sqrt{3}\sqrt{3}-\sqrt{3}+\sqrt{3}-1}\\\\ & =\dfrac{4-2\sqrt{3}}{2}\\\\ & = 2-\sqrt{3}\end{aligned}

7 0
3 years ago
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