1 hour = 4/5 gallon
8 gallon ÷ 4/5
= 8/1 × 5/4
= 40/4
= 10
the answer is A
The sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
<h3>Calculating wavelength </h3>
From the question, we are to determine how many times longer is the first sound wave compared to the second sound water
Using the formula,
v = fλ
∴ λ = v/f
Where v is the velocity
f is the frequency
and λ is the wavelength
For the first wave
f = 20 waves/sec
Then,
λ₁ = v/20
For the second wave
f = 16,000 waves/sec
λ₂ = v/16000
Then,
The factor by which the first sound wave is longer than the second sound wave is
λ₁/ λ₂ = (v/20) ÷( v/16000)
= (v/20) × 16000/v)
= 16000/20
= 800
Hence, the sound wave with a <u>frequency of 20</u> waves/sec is 800 longer than the wavelength of a sound wave with a <u>frequency of 16,000</u> waves/sec
Learn more on Calculating wavelength here: brainly.com/question/16396485
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<h3>
Answer: D. 5 blinks</h3>
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Explanation:
First we'll need to find out how long it takes for the ball to go from the pitcher to the batter.
It needs to travel 60.5 feet and does so at a speed of 121 ft/sec
distance = speed*time
time = distance/speed
time = (60.5 ft)/(121 ft per sec)
time = 0.5 seconds
In half a second, the ball is from the pitcher to the batter.
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An eye blink is 0.1 second which means we can form this equation
0.1 second = 1 blink
We multiply both sides by 5 to get the "0.1 second" to turn into "0.5 seconds".
So,
0.1 second = 1 blink
5*(0.1 second) = 5*(1 blink)
0.5 seconds = <u>5 blinks</u> which points us to choice D.
Answer:
$2.5
120 bagels
Step-by-step explanation:
