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Anni [7]
3 years ago
11

a basketball coach keeps track of the points scored per game for all her players.she gives a trophy to the player with the highe

st mean score at the end of the season. which of the following justifies why she uses the mean instead of the median.

Mathematics
2 answers:
In-s [12.5K]3 years ago
8 0

Answer:

She wants to take unusually good and unusually bad games into account

Step-by-step explanation:

As, while calculating mean, we take into account all the observations be it very low or very high

But while calculating the Median,we arrange our observations in the increasing order and then we check the middle of all observations.

In this way we don't take into account of all the observations and in this way the high and low values i.e. extreme values are neglected.

Hence, the correct option is:

She wants to take unusually good and unusually bad games into account

podryga [215]3 years ago
4 0
The answer would be C. When you calculate the mean, it includes every number for a certain period of time into things and averages it out. The median does not average out all the numbers.
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Total money = 150 + 95 + 210 + 45 + 55 + 165 = $720

Total months is 6

Mean = 720 / 6 = $120

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3 years ago
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ivolga24 [154]

Answer:

it's 3 it's it

Step-by-step explanation:

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3 years ago
Can anyone help me with 3 and 4
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5 0
3 years ago
If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95​% confident that the d
katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Sample size needed

At least n, in which n is found when M = 0.09

We don't know the proportion, so we use \pi = 0.5, which is when we would need the largest sample size.

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.09\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.09}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}

n = 118.6

Rounding up

We need a sample size of least 119

6 0
3 years ago
Andrew has three times as many pens as Owen. Together they have 20 pens. How many pens Andrew have?
Softa [21]
Andrew has 10 pens bc it's half of twenty
3 0
3 years ago
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