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xxTIMURxx [149]
2 years ago
12

There are 12 sixth graders, 11 seventh

Mathematics
1 answer:
Ilya [14]2 years ago
5 0

Answer: 1

Step-by-step explanation:

because there not the only ones on the team

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What is the answer and how do you do this problem?
nadezda [96]

We want to recast the equation into the standard form equation for a circle centered at (h, k) with radius r. That equation is

... (x -h)² + (y -k)² = r²

Start by completing the square for both x-terms and y-terms.

... x² - 4x + y² + 4y = k

To do that, add the squares of half the coefficients of the x- and y-terms.

... x² - 4x + (-2)² + y² + 4y + 2² = k + (-2)² + 2²

... (x -2)² + (y +2)² = k + 8 = r² . . . . . this is now equal to the square of the radius, so we have

... k + 8 = 6² = 36

Subtracting 8 gives

... k = 28 . . . . . . . matches selection D)

7 0
2 years ago
If 2x- 3 + 3x = 28 what is the value of x
andreev551 [17]

Answer:

x= 31/5  (Exact form)

x= 6.2  (Decimal Form)

x= 6 1/5 (Mixed number form)

Step-by-step explanation:

6 0
3 years ago
The triangular arrangement of numbers shown is known as Pascal's triangle. Use inductive reasoning to find the 6 missing numbers
denis-greek [22]

Answer:

1 5 10 10 5 1

Step-by-step explanation:

The complete question has been attached as an image.

Looking at the triangle, we see a pattern. The first level we have 1, in the next level we have 1 1, the next evel we have 1 2 1, the next level we have 1 3 3 1 and so on. From here, we see that to get the numbers of the next level, we have to write 1 as the first number, then add 1 to the next number after it in the previous level to get the second number in the next level then add the second number of the previous level to the next number beside it to get the third number in the next level and so on until you get to the last number before 1 in the previous level, add that number to 1 to get the second to the last number in the next level and finally put 1 as the last number in the next level. Now, we have

1 4 6 4 1

1 5 10 10 5 1

And that is the required set of numbers.

3 0
3 years ago
Factor completely 3bx2 − 9x3 − b + 3x. (b − 3x)(3x2 − 1) (b + 3x)(3x2 + 1) (b + 3x)(3x2 − 1) Prime
Daniel [21]
3bx^2-9x^3-b+3x=\boxed{3x^2}\cdot b-\boxed{3x^2}\cdot3x\fbox{-1}\cdot b\fbox{-1}\cdot (-3x)\\\\=\boxed{3x^2}(b-3x)\fbox{-1}(b-3x)=\boxed{(b-3x)(3x^2-1)}\\\\completely:\\use:a^2-b^2=(a-b)(a+b)\to3x^2-1=(x\sqrt3)^2-1^2=(x\sqrt3-1)(x\sqrt3+1)
therefore:\\3bx^2-9x^3-b+3x=(b-3x)(3x^2-1)\\=\underline{\underline{(b-3x)(x\sqrt3-1)(x\sqrt3+1)}}
6 0
3 years ago
Read 2 more answers
What is the value of the following expression?
monitta

The expression (−81)(−9)  will give the value of 729.

<u>Step-by-step explanation:</u>

The given expression is (−81)(−9) .

The both numbers in the expression are negative numbers and they are given inside the brackets.

This means that, the negative numbers must be multiplied to get a final value.

<u>The rules in multiplication are :</u>

  • Positive number × Positive number = positive number
  • Negative number × Positive number = negative number
  • Positive number × Negative number = negative number
  • Negative number × Negative number = positive number

From the rules, it can be determined that the result of any two negative numbers will be a positive number.

So, eliminate option A) and B) because they have negative sign.

The expression (−81)(−9) = -81 × -9

⇒ 729.

Therefore, the option C) and D) are not in match with 729. None of the options are not the value of the given expression (−81)(−9).

6 0
3 years ago
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