Answer:
b. 
a. ![\displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B8x%20%2B%2012y%5D%5E2%20%2B%20%5B6x%20%2B%209y%5D%5E2%20%3D%20%5B10x%20%2B%2015y%5D%5E2)
Step-by-step explanation:
b. 
a. ![\displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B8x%20%2B%2012y%5D%5E2%20%2B%20%5B6x%20%2B%209y%5D%5E2%20%3D%20%5B10x%20%2B%2015y%5D%5E2)
The two expressions are identical on each side of the equivalence symbol, therefore they are an identity.
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Answer:
Point B
Step-by-step explanation:
Inside the darkest part where both inequalities are true
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Answer:
The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
Step-by-step explanation:
Let the random variable <em>X</em> represent the amount of money that the family has invested in different real estate properties.
The random variable <em>X</em> follows a Normal distribution with parameters <em>μ</em> = $225,000 and <em>σ</em> = $50,000.
It is provided that the family has invested in <em>n</em> = 10 different real estate properties.
Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

Now the lowest 80% of the amount invested can be represented as follows:

The value of <em>z</em> is 0.84.
*Use a <em>z</em>-table.
Compute the value of the mean amount invested as follows:


Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.
We know that 100paise=1 rupee
=>500 paise = 5 rs
ratio =5/20=1/4=1:4
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