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Alexeev081 [22]
2 years ago
14

Can someone please find the slope, no link answers pls

Mathematics
1 answer:
alexdok [17]2 years ago
5 0

Answer:

-3/1

Step-by-step explanation:

The rise is 1 and the the run is 3 but the line goes from top left to top right so its negative.

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(16+5i) + (6-7i)<br>How do I solve this?​
Fantom [35]

Answer:

\large\boxed{(16+5i)+(6-7i)=22-2i}

Step-by-step explanation:

(16+5i)+(6-7i)=16+5i+6+7i\qquad\text{combine like terms}\\\\=(16+6)+(5i-7i)=22-2i

5 0
3 years ago
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-6 (x + 3) =6 <br> distributive property btw
Basile [38]
The answer to -6(x+3)=6 is x= -4

8 0
3 years ago
Someone answer this plzzz​
Zolol [24]

Which one?

       / \

         l

<-------l------->

|            |

Y           Z    

They are now congruent.

Sorry!

It's pretty bad.

5 0
3 years ago
What is the difference written in scientific notation 1.3x10^6 - 6.8 x 10^5
Pavlova-9 [17]

One way to solve this is to revert to integers.

Do this by moving the decimal in 1.3 to the right 6 places (indicated by the positive power value) and then 6.8 move the decimal to the right 5 places (same reason)

Now you have 1,300,000 & 680000. Subtract to get 620,000.

Now convert your product to scientific notation again by moving your decimal to the left until you are left with 6.2 x ? The question mark will be 10 to the number of places you moved the decimal. 10^5

We have 6.2 x 10^5.

It is import to note that when the decimal must be moved to the right for values less than one, the power will be negative.

3 0
3 years ago
Read 2 more answers
What number is 344% of 107
olga55 [171]

Answer:

368.08

So I turn the numbers into fractions so 344% would be 344/100 because percentages are out of 100. Since it is 344% OF 107, you'd put 107 on the bottom of the fraction and the answer will go on top. I multiply the IS with the OF (IS is the top number and OF is the bottom) so you'd multiply 107x344 to get 36808. Since 344 is a percent (out of 100) you have to do divide the answer by 100 to get 368.08

I hope that helps!

8 0
3 years ago
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