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Gennadij [26K]
4 years ago
9

A building casts a 50-foot shadow. Alex is 5 feet tall and casts a 6-foot shadow. Approximately how tall is the building?

Mathematics
2 answers:
Svetradugi [14.3K]4 years ago
7 0

Answer:

Option d is correct.

42 ft(Approximately) tall is the building.

Step-by-step explanation:

Proportion states that the two ratios or fractions are equal.

As per the statement: A building casts a 50-foot shadow.

Also, Alex is 5 feet tall and casts a 6-foot shadow.

⇒ Height of the Alex = 5 ft , Shadow of Alex = 6 ft and Shadow of the building= 50 ft.

Let height of the building be h.

Then, by definition of proportion,

\frac{Height of Alex}{Shadow of Alex} = \frac{Height of the building}{Shadow of the building}

Substitute the given values we get;

\frac{5}{6} = \frac{h}{50}

By cross multiply we get;

50 \times 5 = 6h

Divide both sides by 6 we get;

h = \frac{50 \times 5}{6} = \frac{250}{6} = 41.6666667 ft

Therefore, height of the building (approximately) is, 42 ft

vagabundo [1.1K]4 years ago
5 0
D.   
You have to make a proportion. Set it up 5/6 = x/50. Then cross multiply. 5x50=250. 6 x <em>(x)</em> = 6x. 6x=250. 250/6=41.66666. x=41.6666. Round up, and the building is about 42 ft. tall. 
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