Question

he work shows how to use long division to find (x2 + 3x –9) ÷ (x – 2). What will be the remainder over the divisor?

Answer 1

Answer:

Remainder is 1.

Step-by-step explanation:

Given is an algebraic quadratic function in x as

$x^2+3x-9$

and we have to divide by x-2.

We find that leading terms are x square and x so quotient I term is x.

$x-2) x^2+3x-9(x+5\\ x^2-2x\\ -----------\\ 5x-9\\ 5x-10\\ ----------------\\ +1\\ -----------------$

Hence quotient is x+5 and remainder is 1

Answer 2

remainder = 1

(x² + 3x - 9 )÷ (x - 2 ) =  x + 5 + $\frac{1}{x-2}$