For the first line we have a slope of (y2-y1)/(x2-x1)
(2--2)/(1--1)=4/2=2 so we have:
y=2x+b, now solve for b with either of the points, I'll use: (1,2)
2=2(1)+b
b=0 so the first line is:
y=2x
Now the second line:
(1-10)/(4--2)=-9/6=-3/2 so far then we have:
y=-3x/2+b, using point (4,1) we solve for b...
1=-3(4)/2+b
1=-6+b
b=7 so
y=-3x/2+7 or more neatly...
y=(-3x+14)/2
...
The solution occurs when both the x and y coordinates for each are equal, so we can say y=y, and use our two line equations...
2x=(-3x+14)/2
4x=-3x+14
7x=14
x=2, and using y=2x we see that:
y=2(2)=4, so the solution occurs at the point:
(2,4)
Answer: Option c. D: all real numbers R: (y ≥ 8.75)
Solution:
y=x^2+x+9
Domain: all real numbers = ( - Infinite, Infinite)
y=ax^2+bx+c
a=1 > 0, the parabola opens upward: Range: y ≥k
b=1
c=9
Vertex: V=(h,k)
h=-b/(2a)
h=-1/(2(1))
h=-1/2
h=-0.5
k=y=h^2+h+9
k=(-0.5)^2+(-0.5)+9
k=0.25-0.5+9
k=8.75
Range: y≥k
Range: y≥8.75
Answer:
The range of the equation is y ≥ 9 ⇒ C
Step-by-step explanation:
The quadratic equation y = ax² + bx + c, represents by a parabola of vertex (h, k), where h =
and k is the value of y at x = h
- The range of the quadratic if it has a minimum vertex is y ≥ k, and y ≤ k if it has a maximum vertex
- The parabola has a minimum vertex if the value of a is positive and a maximum vertex if the value of a is negative
∵ The equation is y = x² + 9
→ Compare it with the form above to find a and b
∴ a = 1 and b = 0
∵ a is a positive number
∴ The parabola has a minimum vertex
→ By using the 1st rule above
∴ The range is y ≥ k
→ Use the rule of h above to find it
∵ h =
= 
∴ h = 0
→ To find k substitute x by the value of h and y by k
∵ k = (0)² + 9
∴ k = 0 + 9
∴ k = 9
∴ The range of the equation is y ≥ 9
Answer:
b = 30 / a
which agrees with the third expression in the list of possible options
Step-by-step explanation:
When we say that a and b vary inversely, that means that in mathematical form:
b = k / a where "k" is the so called "constant of proportionality". In order to write the function that models this inverse variation, we need to find the value of "k". We do such by using the information they provide (b = 5/2 when a = 12):
5/2 = k / 12
Then, solving for "k":
5 * 12 / 2 = k
60 / 2 = k
k = 30
Then we can now write the function that models this inverse variation:
b = k / a
b = 30 / a
Well she has 350 so start with 350 then she spends 180 so put -180, you can put remaining as r.
Answer: 350-180=r
r=170