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AVprozaik [17]
3 years ago
13

10. Write an equation in point-slope form for the line through the given point with the given slope.

Mathematics
1 answer:
Norma-Jean [14]3 years ago
6 0

Answer:

C

Step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

here m = 5 and (a, b) = (8, 3), hence

y - 3 = 5(x - 8) → C


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When does the new map in among us come out? They say today but I haven't seen it. Anyone know what time?
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3 years ago
Tyler’s family is using a shipping trailer that is 5 feet tall, 4 feet wide, and 12 feet long to load boxes of apples in. Each b
kogti [31]
Hello.

To get the volume 5184 in3 you can use the dimension 18in x 24in x 12in.

First, you should draw a picture of your shipping container. It is a rectangular prism that is 5 by 12 by 4.

Next, let's look at the boxes of apples that will go into the box. The volume has to be 5184 in^3. If we divide it by 12 and 12, the answer is 3. Therefore, we could make a box that is 1 foot by 1 foot by 3 feet. 

Those boxes would be stack on the base without any left over space. Now, just figure out how many would go on the next rows. They would be able to stand up and down.

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Read 2 more answers
In Exercises 45–48, let f(x) = (x - 2)2 + 1. Match the<br> function with its graph
MA_775_DIABLO [31]

Answer:

45) The function corresponds to graph A

46) The function corresponds to graph C

47) The function corresponds to graph B

48) The function corresponds to graph D

Step-by-step explanation:

We know that the function f(x) is:

f(x)=(x-2)^{2}+1

45)

The function g(x) is given by:

g(x)=f(x-1)

using f(x) we can find f(x-1)

g(x)=((x-1)-2)^{2}+1=(x-3)^{2}+1

If we take the derivative and equal to zero we will find the minimum value of the parabolla (x,y) and then find the correct graph.

g(x)'=2(x-3)

2(x-3)=0

x=3

Puting it on g(x) we will get y value.

y=g(3)=(3-3)^{2}+1

y=g(3)=1

<u>Then, the minimum point of this function is (3,1) and it corresponds to (A)</u>

46)

Let's use the same method here.

g(x)=f(x+2)

g(x)=((x+2)-2)^{2}+1

g(x)=(x)^{2}+1

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2x

0=2x

x=0

Evaluatinf g(x) at this value of x we have:

g(0)=(x)^{2}+1

g(0)=1

<u>Then, the minimum point of this function is (0,1) and it corresponds to (C)</u>

47)

Let's use the same method here.

g(x)=f(x)+2

g(x)=(x-2)^{2}+1+2

g(x)=(x-2)^{2}+3

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}+3

g(2)=3

<u>Then, the minimum point of this function is (2,3) and it corresponds to (B)</u>

48)

Let's use the same method here.

g(x)=f(x)-3

g(x)=(x-2)^{2}+1-3

g(x)=(x-2)^{2}-2

Let's find the first derivative and equal to zero to find x and y minimum value.

g'(x)=2(x-2)

0=2(x-2)

x=2

Evaluatinf g(x) at this value of x we have:

g(2)=(2-2)^{2}-2

g(2)=-2

<u>Then, the minimum point of this function is (2,-2) and it corresponds to (D)</u>

<u />

I hope it helps you!

<u />

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Answer:

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Step-by-step explanation:

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Find three consecutive integers whose sum is negative 21
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-6,-7, and -8, this is more of a guess and check question

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