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4 years ago

Hi everyone do anyone know what is 5+5 equal too thank you so much

Mathematics

2 answers:

SCORPION-xisa [38]4 years ago

8 0

Answer:10

Step-by-step explanation:

You have 5 apples and get 5 you now have 10

Yuki888 [10]4 years ago

6 0

Answer:

Step-by-step explanation:

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The local park has a circular pond with a radius of 9 feet. What is the pond's circumference?

sergiy2304 [10]

Answer:

Using 3.14 as pi, the answer would be 56.52, and using just pi (as in the input on a calculator) would be 56.54867.

Step-by-step explanation:

The equation for circumference of a circle is C = πd, C representing the circumference and d representing the diameter. Since the equation shows the radius, the equation can also be C = 2πr, since the radius is half of the diameter. Multiply nine by two to get eighteen. 18 times 3.14 = 56.52.

8 0

3 years ago

A department store advertised that for every $25 you spend at the store,

Semmy [17]

His claim is resonable 154/25=6 r4 6x2=12

3 0

3 years ago

Read 2 more answers

Indefinate integral of sin-1(x? i know you have to use integral by parts: u = sin-1(x v = x

svet-max [94.6K]

Yes
you let u = sin-1 x and dv = 1 ( so v = x)
and use the rule
INT udv = uv - INT vdu
= x sin^-1 x - INT x sin-1 x

u = sin-1 x so x = sin u
dx/du = cos u , du/dx = 1 / cos u = 1 / sqrt(1 - sin^2) = 1 / sqrt (1-x)^2
so substituting we have

INT sin-1(x) = x sin-1x - INT ( x / sqrt(1- x^2)
= x sun-1 x - ( - sqrt (1 - x^2)
= x sin-1 x + sqrt(1 - x^2) + C

3 0

4 years ago

In 1970 there were 160 African American women in elected public office in the United States. By 1993 the number had increased to

timama [110]

Answer:

Average rate of change for the number of African American women who held office at any given time between 1970 & 1993 is 94.43.

Step-by-step explanation:

Here, according to the question:

Number of African American women in elected public office in the United States in the year 1970 = 160

Number of African American women in elected public office in the United States in the year 1993 = 2332

Now, the change in the number of elected women between 1970 & 1993

= Women elected in the year 1993 - Women elected in the year 1970

= 2332 - 160 = 2,172

or, the change in the number of elected women candidates between 1970 & 1993 is 2,172

Now, the difference in the time period is 1993 - 1970 = 23 years

So, $\textrm{The average rate of change} = \frac{\textrm{Total change in the quantity}}{\textrm{Time Interval}} \\=\frac{2172}{23} = 94.43$

Hence, the average rate of change for the number of African American women who held office at any given time between 1970 & 1993 is 94.43.

6 0

3 years ago

A coin is tossed 20 times. A person, who claims to have extrasensory perception, is asked to predict the outcome of each flip in

Korolek [52]

Answer:

5.77% probability of being correct 14 or more times by guessing

Step-by-step explanation:

For each time the coin is tossed, there are only two possible outcomes. Either the person predicts the correct outcome, or she does not. The probability of predicting the correct outcome in a toss is independent of other tosses. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

A coin is tossed 20 times.

This means that $n = 20$

Fair coin:

Equally as likely to be heads or tails, so $p = \frac{1}{2} = 0.5$

What is the probability of being correct 14 or more times by guessing

$P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 14) = C_{20,14}.(0.5)^{14}.(0.5)^{6} = 0.0370$

$P(X = 15) = C_{20,15}.(0.5)^{15}.(0.5)^{5} = 0.0148$

$P(X = 16) = C_{20,16}.(0.5)^{16}.(0.5)^{4} = 0.0046$

$P(X = 17) = C_{20,17}.(0.5)^{17}.(0.5)^{3} = 0.0011$

$P(X = 18) = C_{20,18}.(0.5)^{18}.(0.5)^{2} = 0.0002$

$P(X = 19) = C_{20,19}.(0.5)^{19}.(0.5)^{1} \approx 0$

$P(X = 20) = C_{20,20}.(0.5)^{20}.(0.5)^{0} \approx 0$

Then

$P(X \geq 14) = P(X = 14) + P(X = 15) + P(X = 16) + P(X = 17) + P(X = 18) + P(X = 19) + P(X = 20) = 0.0370 + 0.0148 + 0.0046 + 0.0011 + 0.0002 + 0 + 0 = 0.0577$

5.77% probability of being correct 14 or more times by guessing

5 0

3 years ago

Hi everyone do anyone know what is 5+5 equal too thank you so much​

Hi everyone do anyone know what is 5+5 equal too thank you so much