This is the easiest way to solve this problem:
Imagine this represents how many combinations you can have for each of the 4 wheels (each blank spot for one wheel): __ __ __ __
For the first situation it says how many combos can we make if no digits are repeated.
We have 10 digits to use for the first wheel so put a 10 in the first slot
10 __ __ __
Since no digit can be repeated we only have 9 options for the second slot
10 9_ __ __
Same for the third slot, so only 8 options
<u>10</u> <u> 9 </u> <u> 8 </u> __
4th can't be repeated so only 7 options left
<u>10</u> <u> 9 </u> <u> 8 </u> <u> 7
</u><u>
</u>Multiply the four numbers together: 10*9*8*7 = 5040 combinations
For the next two do the same process as the one above.
If digits can be repeated? You have ten options for every wheel so it would look like this: <u>10</u> <u>10</u> <u>10</u> <u>10
</u>
10*10*10*10 = 10,000 combinations
If successive digits bust be different?
We have 10 for the first wheel, but second wheel only has 9 options because 2nd number can't be same as first. The third and fourth wheels also has 9 options for the same reason.
<u>10</u> <u> 9</u><u> </u> <u> 9 </u> <u> 9 </u>
10*9*9*9 = 7290 combinations
Answer:

Step-by-step explanation:
If I'm not mistaken by the question, we have

Multiply through by the LCM of all the denominators to clear the fractions. Since we have only one fraction, we multiply through by its LCM (3)


Putting all terms on the LHS (left hand side) and evaluating,

If you simplify it, it would be that same as 2/3.
Answer:
7/40
Step-by-step explanation:
There are 3 girls+9 boys = 12 students in the 7th grade
P (girl in 7th grade) = girls/ total
= 3/12 = 1/4
There are 7 girls+3 boys = 10 students in the 8th grade
P (girl in 8th grade) = girls/ total
= 7/10
P(7th grade girl, 8th grade girl) = 1/4 * 7/10 = 7/40
Answer:
3.75
Step-by-step explanation:
15/4 = 375/100 = 3.75