The probable genotype of the IV-3 with the perspective of autosomal inheritance will be A because he does not have condition A. Therefore both parents must be in condition A.
The probable genotype of IV-3 with the perspective of set=linked inheritance will be BbY this is because he has B condition. Therefore the mothers' genotype must be XBXb and the father's genotype must be XBY.
The probability of IV-4 having condition A is 1/36
Answer:
this means the 2 letters in the genotype can not be both lowercase or both uppercase
Explanation:
Therefore a genotype that is heterozygous will always be heterozygous dominant and will look like Bb
His heart isn't pumping adequately to remove the water from his body due to his weight gain because it takes more for your heart to work correctly if your are over weight
I’d say A is probably the correct answer , but if not A , then definitely B.
The reaction needed to remove glucose molecule from a polysaccharide is hydrolysis.
Glucose is a type of monosaccharide which is used in the body for energy.
These monosaccharides such as:
can combine together to form a larger molecule of sugar known as polysaccharides in a reaction called condensation reaction.
Examples of polysaccharides are
These polysaccharides can also be broken down to form the various monosaccharides that makes them up.
The hydrolysis of polysaccharides involves the breaking of the glycosidic bonds that hold the monomers of a polysaccharide molecule together.
This leads to the formation of monosaccharides such as glucose.
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