Lim x->1 (x^2+8x-2)
substitute x =1
= 1^2 +8(1)-2
= 1 +8 -2
= 7
So the limit = 7
Just add up the lengths of the four sides, and you have the perimeter.
The perimeter is:
(4x-7)*2 + (10x^2+4x-2)*2 =
8x-14 + 20x^2+8x-4 =
20x^2 + 16x - 18
The statement "<span>The rate of change of y with respect to x is inversely proportional to y^4" can be written mathematically as dy/dx = k/y^4
To solve the differential equation, we use variable saparable method.
y^4 dy = kdx
Integrating both sides gives,
y^5 / 5 = kx + A
y^5 = 5kx + 5A = Bx + C; where B = 5k and C = 5A
![y= \sqrt[5]{Bx+C}](https://tex.z-dn.net/?f=y%3D%20%5Csqrt%5B5%5D%7BBx%2BC%7D%20)
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68 should be the answer... Sorry if I'm wrong
A) x/6=9
Subtract 6 from both sides, x=3
B) x/-4=-3
Add 4 to both sides, x=1
C) x/-5=7
Add 5 to both sides, x=12