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stira [4]
3 years ago
8

I'm thinking of two numbers the first number is 3 times the second the second number is 5 less than 2 times the first what are m

y numbers
Mathematics
1 answer:
charle [14.2K]3 years ago
6 0
1= 14
2= 9               hope you get how i solved!
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2(x+50)=16+4x<br> What is x?
Leona [35]
2x +100=16+4x
-2x. -2x
100=16+2x
-16. -16
84=2x
divide both sides
x=42
4 0
2 years ago
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HELP ME PLEASE! I am not good at math
Diano4ka-milaya [45]
First you subtract 1/3 from both sides, that leaves you with 5/12, then you multiply the reciprocal of 1/2 by both sides, which is 2, which gives you 5/6. Therefore, K>5/6
4 0
2 years ago
Find the value of x <br> if necessary, you may learn what The markings on a figure indicate
Anvisha [2.4K]

Answer:

68°is the value of x. hope this helps

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2 years ago
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Step by step please and thank you.
cupoosta [38]

Answer:

  the probability is 2/9

Step-by-step explanation:

Assuming the coins are randomly selected, the probability of pulling a dime first is the number of dimes (4) divided by the total number of coins (10).

  p(dime first) = 4/10 = 2/5

Then, having drawn a dime, there are 9 coins left, of which 5 are nickels. The probability of randomly choosing a nickel is 5/9.

The joint probability of these two events occurring sequentially is the product of their probabilities:

  p(dime then nickel) = (2/5)×(5/9) = 2/9

_____

<em>Alternate solution</em>

You can go at this another way. You can list all the pairs of coins that can be drawn. There are 90 of them: 10 first coins and, for each of those, 9 coins that can be chosen second. Of these 90 possibilities, there are 4 dimes that can be chosen first, and 5 nickels that can be chosen second, for a total of 20 possible dime-nickel choices out of the 90 total possible outcomes.

  p(dime/nickel) = 20/90 = 2/9

8 0
3 years ago
An electric sale gives a reading equal to the true weight plus a random error that isnormally distributed with mean 0 and standa
Pepsi [2]

Answer:

a) 95% confidence interval estimate of the true weight is (3.026, 3.274)

b) 99% confidence interval estimate of the true weight is (2.944, 3.356)

Step-by-step explanation:

Confidence Interval can be calculated using M±ME where

  • M is the mean of five successive weightings (3.150)
  • ME is the margin of error from the mean

And margin of error (ME) can be calculated using the formula

ME=\frac{t*s}{\sqrt{N} } where

  • t is the corresponding statistic in the given confidence level and degrees of freedom(t-score)
  • s is the standard deviation of the random error (0.1)
  • N is the sample size (5)

Using the numbers 95% confidence interval estimate of the true weight is:

3.150±\frac{2.776*0.1}{\sqrt{5} }≈3.150±0.124

And 99% confidence interval estimate of the true weight is:

3.150±\frac{4.604*0.1}{\sqrt{5} }≈3.150±0.206

3 0
3 years ago
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