Hello from MrBillDoesMath!
Answer:
(3/4) a^(-5)b^(-3)c^2
Discussion:
(18 a^-3b^2c^6)/ (24 a^2b^5c^4) =
(18/24) a^ (-3-2) b^(2-5) c^(6-4) =
as a^-3/a^-2 = a ^ (-3-2) = a^(-5), for examples
(3/4) a^(-5)b^(-3)c^2
Thank you,
MrB
The cost of 1 adult ticket in the off season is 42$, but it is asking for the child ticket's price so you would do 194-42 and you get 152. Then, you would divide 152/4 and you get 38 but this is during the off-season so you would double it and get 76.
The regular price for a child is 76$
But feel free to check my work :D
Answer:
Option B is correct
Step-by-step explanation:
Hope that helped u
➻ In a group of 40 people, 27 can speak English and 25 can speak Spanish.
➻ The required number of people who can speak both English and Spanish .
<u>Consider</u> ,
➻ A → Set of people who speak English.
➻ B → Set of people who speak Spanish
➻ A∩B → Set of people who can speak both English and Spanish
➻ n(A∪B) = n(A) + n (B) - n(A∩B)
➻ 40 = 27 + 25 - n (A∩B)
➻ 40 = 52 - n (A∩B)
➻ n (A∩B) = 52 - 40
➻ ∴ n (A∩B) = 12
∴ Required Number of persons who can speak both English and Spanish are <u>12 .</u>
━━━━━━━━━━━━━━━━━━━━━━
➻ n(A∪B) = n(A) + n (B) - n(A∩B)
➻ 40 = 27 + 25 - 12
➻ 40 = 52 - 12
➻ 40 = 40
➻ ∴ L.H.S = R.H.S
━━━━━━━━━━━━━━━━━━━━━━
Answer:
£30
Step-by-step explanation:
Let Brian initially had money in his wallet = £x
and Colin had the money = £y
Since ratio of money in Brian's wallet to Colin's wallet was 5 : 1
Therefore,
⇒ x = 5y -------(1)
Brian spent £27 that day, so money left with him = £(x - 27)
After spending the money Brian had £3 less than Colin.
(x - 27) = (y - 3)
x = y + 27 - 3
x = y + 24 -------(2)
Now we equate the equations (1) and (2) for the value of x,
5y = y + 24
5y - y = 24
4y = 24
y = £6
From equation (2),
x = 6 + 24
x = £30
Therefore, Brian initially had £30.
i hope this helps
