Answer:
Step-by-step explanation:
→ Substitute in the numbers
→ Simplify
We know that sin2x=2sinxcosx
(search the net for proof if you wish)
So the original equation becomes
2sinxcosx-sinx=0
The two terms both have sinx that can be taken out to get:
sinx(2cosx-1)=0
This is true if sinx=0 or 2cosx-1=0 , rewritten: cosx=1/2
sinx=0 than x=2kπ
cosx=1/2 than x=π/3+2kπ
where k is an integer
Answer:
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
Step-by-step explanation:
IQR = Q₃ - Q₁
For the town A:
Q₃ = 40 and Q₁ = 20
IQR of town A = 40 - 20 = 20
For the town B:
Q₃ = 30 and Q₁ = 20
IQR of town A = 30 - 20 = 10
Check the given options:
The most statement is appropriate comparison of the spreads is B
<u>B. The interquartile range (IQR) for town A, 20, is greater than the</u>
<u>IQR for town B, 10.</u>
<u />
X > 4
divide 6 on both sides hence 24/6 = 4
Answer:
The value of cos Ф is ± 
Step-by-step explanation:
There are important rules for sin Ф and cos Ф
∵ sin Ф = 
∴ sin²Ф = 
∴ sin²Ф = 
→ By using the third rule above
∵ cos²Ф = 1 - sin²Ф
∴ cos²Ф = 1 -
∴ cos²Ф = 
→ Take square root for both sides
∴ cos Ф = ±
∴ The value of cos Ф is ±
