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soldi70 [24.7K]
4 years ago
10

Show me how to do this please for geometry!!

Mathematics
1 answer:
ololo11 [35]4 years ago
4 0

Answer:

see explanation

Step-by-step explanation:

Since the triangles are right use trigonometric ratios to find x and y

A

sin33° = \frac{adjacent}{hypotenuse} = \frac{2.5}x}

Multiply both sides by x

x × sin33° = 2.5 ( divide both sides by sin33° )

x = \frac{2.5}{sin33} ≈ 4.590

tan33° = \frac{opposite}{adjacent} = \frac{2.5}{y}

Multiply both sides by y

y × tan33° = 2.5 ( divide both sides by tan33° )

y = \frac{2.5}{tan33} ≈ 3.850

B

cos72° = \frac{adjacent}{hypotenuse} = \frac{6}{x}

Multiply both sides by x

x × cos72° = 6 ( divide both sides by cos72° )

x = \frac{6}{cos72} ≈ 19.416

tan72° = \frac{y}{6}

Multiply both sides by 6

6 × tan72° = y, thus

y ≈ 18.466

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\begin{gathered} OX^2=XY^2+OY^2 \\ 10^2=5^2+OY^2 \\ 100=25+OY^2 \\ OY^2\text{ = 100 -25} \\ OY^2\text{ = 75} \\ OY\text{ = }\sqrt[]{75} \\ OY\text{ = }\sqrt[]{25\text{ }\times\text{ 3}} \\ OY\text{ = 5}\sqrt[]{3\text{ }}in \end{gathered}

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