On two tests so far this year, a student received a 78 and a 93. The student wants an average between 80 and 90 inclusive. What
1 answer:
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Solution :
Let the three places be 1, 2, 3, 4, 5, 6, 7, 8
a). Number of the cases when a general manager is the next to a vice president is equal to 7 and the these 2 can be arranged in 21 ways. So the total number of ways = 7 x 2
= 14
[(1,2)(2,1) (2,3)(3,2) (3,4)(4,3) (4,5)(5,4) (5,6)(6,5) (6,7)(7,8) (8,7)(7,6)]
Therefore the required probability is
=
b). The probability that the marketing director to be placed in the leftmost position is
c). The two events are not independent because
where A is the case a and B is the case b.
Answer:
Option c. The result is significant at the 0.020.02 level.
Step-by-step explanation:
We are given the following in the question:
We are conducting a one tailed hypothesis test with alternate hypothesis
The z test calculated for the same is
z=2.3
We calculate the p-value from the standard normal table.
p value = 0.010724 at 0.05 significance level.
The result is significant
p value = 0.010724 at 0.01 significance level.
The result is not significant
p value = 0.010724 at 0.02 significance level.
The result is significant at 0.02 significance level.
Thus, the correct answer is
Option c. The result is significant at the 0.020.02 level.