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natka813 [3]
3 years ago
14

Please solve, due tomorrow!

Mathematics
1 answer:
Darya [45]3 years ago
4 0
5x=25  X= 5
X/3=7  X= 21
2x=14  X= 7
x/2=12 X=6
x/4=6   X=24

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Evaluate the expression when z=7 3z+8
SSSSS [86.1K]

Answer:

Hi! The answer to your question is 29

Step-by-step explanation:

3(7)+8

3(7) = 21

21 + 8

= 29

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How do you solve 3y-2=8x-32
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Y=8/3x-10 is the answer in slope intercept form
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Give B= {a,l,g,e,b,r} and C={m,y,t,h} find B U C
masha68 [24]

The union of a collection of sets is the set of all elements in the collection.

We have B = {a, l, g, e, b, r} and C = {m, y, t, h}

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6 0
3 years ago
true or false If x represents a random variable with mean 114 and standard deviation 40, then the standard deviation of the samp
Goshia [24]

Answer:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

Step-by-step explanation:

Let X the random variable of interest and we know that the true mean and deviation for this case are given by:

\mu = 114, \sigma = 40

We also know that we select a sample size of n =100 and on this case since the sample size is higher than 30 we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And the standard deviation for the sampling distribution would be:

\sigma_{\bar X}= \frac{40}{\sqrt{100}}= 4

So then the answer is TRUE

6 0
3 years ago
Find f(-2) if f(x) = x + x + 7. f(-2) =
viktelen [127]

Answer:

f(-2) = 3

Step-by-step explanation:

Given that,

f(x) = x + x + 7

We need to find the value of f(-2).

Put x = -2 in the given function.

f(-2) = (-2) + (-2) + 7

= -2-2+7

= -4+7

= 3

Hence, the value of f(-2) is equal to 3.

3 0
2 years ago
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