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pashok25 [27]
3 years ago
10

It for math and we urge learning about slopes. I don’t know really how to find the slope of a line

Mathematics
1 answer:
kykrilka [37]3 years ago
6 0

Step-by-step explanation:

Get a line of which you want to know the slope.

Pick any two coordinates that the line goes through.

Subtract the two y-coordinates from one another.

Subtract the two x-coordinates from one another.

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Between which two rational numbers is squar root of 3 located
inessss [21]
We know that;

1 ^{2}  = 1 \\ 2^{2}  = 4 \\ 

And 3 is between 1 and 4, therefore;\\ \boxed{1  \leq  \sqrt{3}  \leq 2 }


3 0
3 years ago
What is the equation of a line that passes through the point (8, −2) and is parallel to the line whose equation is 3x + 4y = 15?
Dafna1 [17]

Step 1

<u>Find the slope of the given line</u>

we have

3x+4y=15

Isolate the variable y

Subtract 3x both sides

3x+4y-3x=15-3x

4y=-3x+15

Divide by 4 both sides

y=-\frac{3}{4}x+ \frac{15}{4}

the slope of the given line is

m=-\frac{3}{4}

Step 2

Find the equation of the line that passes through  the point (8,-2) and is parallel to the given line

we know that

if two lines are parallel, then their slopes are equal

The equation of the line into point-slope form is equal to

y-y1=m(x-x1)

we have

m=-\frac{3}{4}

(x1,y1)=(8,-2)

substitute in the equation

y+2=-\frac{3}{4}(x-8)

y=-\frac{3}{4}x+6-2

y=-\frac{3}{4}x+4  or  3x+4y=16

therefore

<u>the answer is</u>

y=-\frac{3}{4}x+4

or

3x+4y=16

8 0
3 years ago
Algebra question, please show work :))
WITCHER [35]

I dont know why but a moderator deleted my answer but I hope that you got it. It was actually A. since it was the quotient of 9 not the quotient of x.

Have a great day hon and I hope that this helped you out a lil:)

5 0
3 years ago
Read 2 more answers
The variance can never bea.zerob.larger than the standard deviationc.negatived.smaller than the standard deviation
MrRa [10]

Answer:

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

Step-by-step explanation:

We need to remember that the variance is a measure of dispersion for a dataset respect to a measure of central tendency called the mean. The mean is defined as:

\bar x = \frac{\sum_{i=1}^n X_i}{n}

And the population mean is given by:

\mu= \frac{\sum_{i=1}^n X_i}{N}

The population variance is defined by:

\sigma^2 = \frac{\sum_{i=1}^n (X_i -\mu)^2}{N}

And the sample variance is defined as:

s^2= \frac{\sum_{i=1}^n (X_i -\bar x)}{n-1}

Now if we analyze the options we have this:

a.zero

False, if all the values are the same then the mean would be the same to the values and the difference between each value and the mean would 0 and indeed the variance would be 0.

b.larger than the standard deviation

False, if the population standard deviation is \sigma=2 then the variance would be \sigma^2 = 4 and as we can see is higher than the standard deviation

c.negative

True, by definition since the variance take in count the differences around the mean squared, then we can't have a negative value for a sum of square values.

d.smaller than the standard deviation

False, if the population standard deviation is \sigma=0.1 then the variance would be \sigma^2 = 0.01 and as we can see is lower than the standard deviation

7 0
3 years ago
Find the missing length indicated.
Andrews [41]

Answer:

<h3>x=144</h3>

Step-by-step explanation:

h²=65²-25²=4225-625=3600

h²=x*25

x=h²:25

x=3600:25

<h3>x=144</h3>
8 0
3 years ago
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