Answer:
see image...
start with Graphing Form: y = a(x-h)²+ k
knowing that h is the x value (negative of it) of the vertex , and k is the y value of the vertex
Graphing Form Equation: y = a(x+3)²+32
you are also given that when the x value is 5 the y value has to be 0
0 = a(4)^2 + 32
a has to be - 1/2
Step-by-step explanation:
The tower is 61.65 meters tall.
<u>SOLUTION: </u>
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,
Then, (let it be) n meter tall 36.25 long shadow
So, by cross multiplication method,
This can be written as,
Cross multiplications steps: (To find Single Variable)
Answer:
Step-by-step explanation:
AC = length of flagpole = 12 ft
AB = length of shadow = 14 ft
BC = length from the top of the flagpole to the end of the shadow = x ft
Use Pythagorean theorem to find the length of x,
x² = AC² + BC²
= 12² + 14²
= 144 + 196
= 340
x = √340
x = 18.4 ft
