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ycow [4]
3 years ago
5

An item is regularly priced at $15. It is on sale for 60% off the regular price. What is the sale price?​

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:

$15 - 60% = $6.00

https://www.percent-off.com/_30_%25+off_39.98_

(I used this website because I lost my calutor, plus I use it to help my mom shop)

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A public health organization reports that 40%of baby boys 6-8 months old in the United
Sveta_85 [38]

Using the binomial distribution, the probabilities are given as follows:

  • 0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.
  • 0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.
  • Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

<h3>What is the binomial distribution formula?</h3>

The formula is:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

The values of the parameters for this problem are:

n = 10, p = 0.4.

The probability that more than 4 weigh more than 20 pounds is:

P(X > 4) = 1 - P(X \leq 4)

In which:

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

Then:

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.4)^{0}.(0.6)^{10} = 0.0061

P(X = 1) = C_{10,1}.(0.4)^{1}.(0.6)^{9} = 0.0403

P(X = 2) = C_{10,2}.(0.4)^{2}.(0.6)^{8} = 0.1209

P(X = 3) = C_{10,3}.(0.4)^{3}.(0.6)^{7} = 0.2150

P(X = 4) = C_{10,4}.(0.4)^{4}.(0.6)^{6} = 0.2502

Hence:

P(X \leq 4) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.0061 + 0.0403 + 0.1209 + 0.2150 + 0.2502 = 0.6325

P(X > 4) = 1 - P(X \leq 4) = 1 - 0.6325 = 0.3675

0.3675 = 36.75% probability that more than 4 weigh more than 20 pounds.

The probability that fewer than 3 weigh more than 20 pounds is:

P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0061 + 0.0403 + 0.1209 = 0.1673

0.1673 = 16.73% probability that fewer than 3 weigh more than 20 pounds.

For more than 7, the probability is:

P(X > 7) = P(X = 8) + P(X = 9) + P(X = 10)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 8) = C_{10,8}.(0.4)^{8}.(0.6)^{2} = 0.0106

P(X = 9) = C_{10,9}.(0.4)^{9}.(0.6)^{1} = 0.0016

P(X = 10) = C_{10,10}.(0.4)^{10}.(0.6)^{0} = 0.0001

Since P(X > 7) < 0.05, it would be unusual if more than 7 of them weigh more than 20 pounds.

More can be learned about the binomial distribution at brainly.com/question/24863377

#SPJ1

4 0
2 years ago
Write and solve a system of equations made up of Aiden's and Natalie's lines of best fit that they can use
dezoksy [38]

The catapult arm length for their tennis balls to cover the same distance is 32.3 feet.

A linear equation is in the form:

y = mx + b

where y, x are variables, m is the rate of change and b is the initial value of y.

Given the equations:

Aiden: y = 2.3x + 160.7

Natalie: y = 3.6x + 202.6

For their tennis balls to cover the same distance:

2.3x + 160.7 = 3.6x + 202.6

1.3x = -41.9

x = -32.3

The catapult arm length for their tennis balls to cover the same distance is 32.3 feet.

Find out more on linear equation at: brainly.com/question/14323743

7 0
3 years ago
Need help with this geometry
Rasek [7]

Answer:

y = 2

Step-by-step explanation:

The mid segment HJ is half of the third side GK , that is

HJ = \frac{1}{2} GK , substitute values

2y = \frac{1}{2} (y + 6) ← multiply both sides by 2 to clear the fraction

4y = y + 6 ( subtract y from both sides )

3y = 6 ( divide both sides by 3 )

y = 2

3 0
2 years ago
Solve the problem. The half-life of plutonium-234 is 9 hours. If 50 milligrams is present now, how much will be present in 6 day
MaRussiya [10]

Answer:

  4)  0.001

Step-by-step explanation:

The amount (a) present in h hours is ...

  a(h) = (initial value)×(1/2)^(h/(half-life))

6 days is 6×24 hours, so the amount remaining is ...

  a(6×24) = 50×(1/2)^(6×24/9) = 50/2^16 ≈ 0.001 . . . . milligrams

3 0
3 years ago
Given that f(x) =<br> X + 3/2<br> a) Find f(2)<br> b) Find f^-1(x)<br> c) Find f^-1(12)
zysi [14]
A) x+3/2
b) x/f
c) 12/f


Mark brainliest please


Hope this helps you
5 0
2 years ago
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