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e-lub [12.9K]
3 years ago
6

A 75 lb boy and a 65 lb girl play on a seesaw. The seesaw is 14 ft long and is pivoted exactly in the middle. If the girl sits o

n the end of her side, where must the boy sit to make the seesaw balance?
Mathematics
1 answer:
GREYUIT [131]3 years ago
5 0

Answer:  6 feet from the pivot point

<u>Step-by-step explanation:</u>

Girl's weight x distance from center = Boy's weight x distance from center

65 (7) = 75x

\dfrac{65(7)}{75}=x

6.066 = x

The boy needs to be placed 6 feet from the center (aka pivot point) which is the same as saying 1 foot from the end of the seesaw.

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