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GenaCL600 [577]
3 years ago
12

Are the following expressions equivalent 26-(-26) and 26+(-26)

Mathematics
1 answer:
kotegsom [21]3 years ago
5 0

Answer:

No.

Step-by-step explanation:

They are not because the left side is 52, while the right side is 0.

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Rationalise 5 divide by square root of 12
Fantom [35]

Answer:

  (5√12)/12

Step-by-step explanation:

In general, 1/√a can be rationalized as (√a)/a. That is the denominator can be multiplied by the square root of the same number to rationalize it. The numerator needs to be multiplied by the same square root.

 \dfrac{5}{\sqrt{12}}=\dfrac{5}{\sqrt{12}}\cdot\dfrac{\sqrt{12}}{\sqrt{12}}=\boxed{\dfrac{5\sqrt{12}}{12}}

4 0
2 years ago
Select the correct inequality sign to make the statements true.
My name is Ann [436]

Answer:

< then >

Step-by-step explanation:

11 7/8 can be written as (11 + 7/8). If we find (11+7/8)², we know that √(11+7/8)² = (11+7/8), so we can compare (11+7/8)² with 129 and see which is bigger.

(11+7/8)² = (11+7/8) * (11+7/8)

= 121 + 7/8 * 11 + 7/8 * 11 + (7/8)²

= 121 + 77/8 + 77/8 + (7/8)²

77/8 is greater than 9 (8*9 = 72) but less than 10 (8*10=80). Rounding down to 7, we have

121 + 7 + 7 + (7/8)²

= 135 + (7/8)²

Even when rounding down, (11+7/8)² is greater than 129. Therefore,

129 < (11+7/8)²

square root both sides

√129 < (11+7/8)

We can apply a similar process for the next one.

(3+5/6)² = (3+5/6) * (3+5/6)

= 9 + 5/6 * 3 + 5/6 * 3 + (5/6)²

= 9 + 15/6 + 15/6 + (5/6)²

15/6 is less than 3 (6*3 = 18) but greater than 2 (6*2 = 12). Rounding down to 2, we have

9 + 2 + 2 + (5/6)²

= 13 + (5/6)² > 10

Even when rounding down, (3+5/6)² is greater than 10

(3+5/6)² > 10

square root both sides

(3+5/6) > √10

8 0
3 years ago
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