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Ymorist [56]
2 years ago
9

Here is a tree diagram showing the sample space for two independent events. How many outcomes are there for the second event?

Mathematics
1 answer:
kobusy [5.1K]2 years ago
8 0

Answer:

probably 8 just remember

________________________________________________________

sick of crying  

tired of trying

yes i'm smiling

but inside i'm  

       dying

Step-by-step explanation:

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A. T=s
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Suppose you want to estimate the proportion of traditional college students on your campus who own their own car. From research
Lapatulllka [165]

Answer:

2,655 students

Step-by-step explanation:

The z-score for a 99% confidence interval is z = 2.576

The standard error for a proportion p is:

SE = z*\sqrt{\frac{p*(1-p)}{n} }

For a proportion of p =0.20, in order to ensure a standard error of 0.02, the sample size 'n' must be:

0.02 = 2.576*\sqrt{\frac{0.2*(1-0.2)}{n}}\\n=2,654.31

Rounding up to the next whole student, the sample size needed is 2,655 students.

5 0
3 years ago
Scott is four more than double the age of Todd. Scott is 56. What is Todd's age?
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Answer: 26 years old

Step-by-step explanation:

Since Scott is four more than double the age of Todd, start by taking away four from Scott's age.

56-4=52

Then take half of that because that would be double of Todd's age

52/2=26

Todd is 26 years old.

5 0
2 years ago
A map of your town has a scale of 1 inch to 0.25 mile. There are two roads that are 5 inches apart on the map. What is the actua
tatiyna
If 1 inch is .25 miles then all you have to do is multiply .25 miles by 5 inches and u get 1.25 miles.
4 0
3 years ago
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X-y=5 and x^2y=5x+6​
sergeinik [125]

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

<h3>How to solve a system of equations</h3>

In this question we have a system formed by a <em>linear</em> equation and a <em>non-linear</em> equation, both with no <em>trascendent</em> elements and whose solution can be found easily by algebraic handling:

x - y = 5      (1)

x² · y = 5 · x + 6       (2)

By (1):

y = x + 5

By substituting on (2):

x² · (x + 5) = 5 · x + 6

x³ + 5 · x² - 5 · x - 6 = 0

(x + 5.693) · (x - 1.430) · (x + 0.737) = 0

There are three solutions: x₁ ≈ 5.693, x₂ ≈ 1.430, x₃ ≈ - 0.737

And the y-values are found by evaluating on (1):

y = x + 5

x₁ ≈ 5.693

y₁ ≈ 10.693

x₂ ≈ 1.430

y₂ ≈ 6.430

x₃ ≈ - 0.737

y₃ ≈ 4.263

By applying algebraic handling on the two equations, we find the following three <em>solution</em> pairs: x₁ ≈ 5.693 ,y₁ ≈ 10.693; x₂ ≈ 1.430, y₂ ≈ 6.430; x₃ ≈ - 0.737, y₃ ≈ 4.263.

To learn more on nonlinear equations: brainly.com/question/20242917

#SPJ1

8 0
2 years ago
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