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Svetllana [295]

4 years ago

11

Use the method of cylindrical shells to find the volume of the solid obtained by rotating the region bounded by the given curves

about the x-axis. y = x3/2, y = 8, x = 0

1 answer:

Igoryamba4 years ago

6 0

Solve for the value of x such that f(x)=8
imma assume it is y=x^(3/2)
so
solve 8=x^(3/2)
x=4
so integrate from x=0 to x=4
$\pi \int\limits^4_0 {(x^ \frac{3}{2})^2 } \, dx$ is the area
$\pi \int\limits^4_0 {x^3 } \, dx$ =
$\pi [ \frac{1}{4}x^4 ]^4_0$ =
$\pi (4^3)$ =
64π cubic units

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Crystal has $13 to spend on apples and oranges. If she buys her apples first and spends more than $8, which expression represent

kumpel [21]

Answer:

b) d<5

Step-by-step explanation:

This is because she started of with $13 and she spent more than $8 on apples so she has less than $5 to spend on oranges

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3 years ago

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Marguerite wants to rent a carpet cleaner. Company A rents a carpet cleaner for $15 per day. Company B rents a carpet cleaner fo

Jet001 [13]

Answer:

If Marguerite rents for 2 weeks, it will cost her less if she rents from Company B

If Marguerite rents for 1 week, it will cost her the same at either company

h(x) = 5x - 5

Step-by-step explanation:

Marguerite wants to rent a carpet cleaner. Company A rents a carpet cleaner for $15 per day. Company B rents a carpet cleaner for $100 per week, with a one-time fee of $5. The following functions represent the rate structures of the two rental companies: x = the number of weeks Company A f(x) = 15(7x) Company B g(x) = 100x + 5 The function h(x) = f(x) – g(x) represents the difference between the two rate structures. Determine which statements about h(x) and about renting a carpet cleaner are true. Check all that apply. If Marguerite rents for 2 weeks, it will cost her more if she rents from Company B. If Marguerite rents for 2 weeks, it will cost her less if she rents from Company B. If Marguerite rents for 1 week, it will cost her the same at either company. If Marguerite rents for 1 week, it will cost her more if she rents from Company A. h(x) = 5x – 5 h(x) = 5x + 5

Answer: Company A rents a carpet cleaner for $15 per day. Company B rents a carpet cleaner for $100 per week, with a one-time fee of $5. In one week there are 7 days, therefore in x weeks the cost of rentals are given below:

For company A: f(x) = 15(7x)

For company B: g(x) = 100x + 5

h(x) = f(x) – g(x) represents the difference between the two rate structures.

h(x) = f(x) - g(x) = 15(7x) - (100x + 5)

h(x) = 105x - 100x - 5

h(x) = 5x - 5

If Marguerite rents for 2 weeks:

The cost for company A = 15(7x) = 15(7 × 2) = $210

The cost for company B = 100x + 5 = 100(2) + 5 = 200 + 5 = $205

If Marguerite rents for 2 weeks, it will cost her less if she rents from Company B

If Marguerite rents for 1 weeks:

The cost for company A = 15(7x) = 15(7 × 1) = $105

The cost for company B = 100x + 5 = 100(1) + 5 = 100 + 5 = $105

If Marguerite rents for 1 week, it will cost her the same at either company

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4 years ago

1. Subtract the linear expressions.

jeyben [28]

$(1)\\\\(45x -5) -(13x +4) = 45x-5-13x -4 = 32x -9\\\\\\(2)\\\\-2(4n) -3 + (-7)(8n) +2 = -8n-56n -1 = -64n -1 = -(64n+1)\\\\(3)\\\\(-3.6x+9.4) - (1.9x +3.6) = -3.6x +9.4 -1.9x -3.6 =-5.5x+5.8\\\\\\(4)\\\\-3x+4-(5x-2) = -3x+4-5x +2=-8x +6$

7 0

3 years ago

Learning Task 1 4/625 11. 796 A. Simplify the radical expressions 1. V63 6. V24 2. 48 7. 781 3. 775 8. V128 4. 99 9. 340 5. 92 1

kompoz [17]

Question:

Simplify the radical expressions

$1.\ \sqrt{63$ $2.\ \sqrt{48$ $3.\ \sqrt{75$ $4.\ \sqrt{99$ $5.\ \sqrt{92$

$6.\ \sqrt[3]{24}$ $7.\ \sqrt[3]{81}$ $8.\ \sqrt{128}$ $9.\sqrt[3]{40}$ $10.\ \sqrt[3]{135}$

Answer:

$\sqrt{63}= 3 \sqrt7$

$\sqrt{48} = 4\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$\sqrt{99} = 3 \sqrt{11$

$\sqrt{92} = 2\sqrt{23$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$\sqrt{128} = 8 \sqrt{2}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

Step-by-step explanation:

$1.\ \sqrt{63$

Express 63 as 9 * 7

$\sqrt{63}= \sqrt{9 * 7$

Split:

$\sqrt{63}= \sqrt{9} * \sqrt7$

$\sqrt{63}= 3 * \sqrt7$

$\sqrt{63}= 3 \sqrt7$

$2.\ \sqrt{48$

Express 48 as 16 * 3

$\sqrt{48} = \sqrt{16*3}$

Split

$\sqrt{48} = \sqrt{16}*\sqrt{3}$

$\sqrt{48} = 4*\sqrt{3}$

$\sqrt{48} = 4\sqrt{3}$

$3.\ \sqrt{75$

Express 75 as 25 * 3

$\sqrt{75} = \sqrt{25*3}$

Split

$\sqrt{75} = \sqrt{25}*\sqrt{3}$

$\sqrt{75} = 5\sqrt{3}$

$4.\ \sqrt{99$

Express 99 as 9 * 11

$\sqrt{99} = \sqrt{9} * \sqrt{11}$

Split

$\sqrt{99} = 3 \sqrt{11$

$5.\ \sqrt{92$

Express 92 as 4 * 23

$\sqrt{92} = \sqrt{4} * \sqrt{23$

$\sqrt{92} = 2* \sqrt{23$

$\sqrt{92} = 2\sqrt{23$

$6.\ \sqrt[3]{24}$

Express 24 as 8 * 3

$\sqrt[3]{24} = \sqrt[3]{8} * \sqrt[3]{3}$

Express 8 as 2^3

$\sqrt[3]{24} = \sqrt[3]{2^3} * \sqrt[3]{3}$

$\sqrt[3]{24} = 2 \sqrt[3]{3}$

$7.\ \sqrt[3]{81}$

Express 81 as 27 * 3

$\sqrt[3]{81} =\sqrt[3]{27}*\sqrt[3]{3}$

Express 27 as 3^3

$\sqrt[3]{81} =\sqrt[3]{3^3}*\sqrt[3]{3}$

$\sqrt[3]{81} =3\sqrt[3]{3}$

$8.\ \sqrt{128}$

Express 128 as 64 * 2

$\sqrt{128} = \sqrt{64} * \sqrt{2}$

$\sqrt{128} = 8 \sqrt{2}$

$9.\sqrt[3]{40}$

Express 40 as 8 * 5

$\sqrt[3]{40} = \sqrt[3]{8} * \sqrt[3]{5}$

$\sqrt[3]{40} = \sqrt[3]{2^3} * \sqrt[3]{5}$

$\sqrt[3]{40} = 2 \sqrt[3]{5}$

$10.\ \sqrt[3]{135}$

Express 135 as 27 * 5

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

Express 27 as 3^3

$\sqrt[3]{135} =\sqrt[3]{27}*\sqrt[3]{5}$

$\sqrt[3]{135} =3\sqrt[3]{5}$

4 0

3 years ago

Which of the following represents 3x - 5y + 10 = 0 written in slope-intercept form

nalin [4]

$The\ slope-intercept\ form:y=mx+b\\\\3x-5y+10=0\ \ \ |add\ 5y\ to\ both\ sides\\\\3x+10=5y\\\\5y=3x+10\ \ \ \ |divide\ both\ sides\ by\ 5\\\\\boxed{y=\frac{3}{5}x+2}$

6 0

3 years ago