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soldier1979 [14.2K]
3 years ago
12

There are ten shirts in your closet, four blue, three green, and three red. You randomly select a different shirt each day. You

wear a blue shirt Monday, Tuesday, and Wednesday.
Mathematics
2 answers:
Law Incorporation [45]3 years ago
7 0
It's a probability problem to find the odds of picking a green or red shirt out of the 10 shirts on Thursday, Friday and Saturday since you have randomly already know you have picked a blue shirt on the other days. Not sure if you have this as a multiple question problem as you didn't list any possible answers (A. 7/20, B. 5/47, C. 2/5, D. 4/125) to the question. A, B, C, D being like 7 chances out of 20, 5 chances out 47, 2 chances out of chances 5 or 4 chances out of 125 (example answers only).

Probability = Number favorable outcomes / total number of outcomes





LenaWriter [7]3 years ago
4 0
If you're asking for the probability of drawing said shirt colors on said days:
Assuming there's no replacement (because clothes), the answer would be:
(2/5)•(1/3)•(1/4), which equals 2/60, or 1/30.
The reason:
On Monday, there are 10 shirts, 4 of them blue. So, your chances are 4 out of 10, or 4/10, which reduces to 2/5.
On Tuesday, there are 9 shirts left, 3 of them blue. So, 3/9, or 1/3.
On Wednesday, there are 8 shirts, 2 of them blue. So, 2/8, or 1/4.
You multiply all the fractions together (which is why simplifying helps A TON)
Hope this helps! And sorry about not answering sooner!
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Step-by-step explanation:

Given : Population Growth The population P (in thousands) of Oriando,Florida from 1980 through 2009 can be modeled by p = 130e^{0.0205t}    (1)

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a. ⇒The population of Phoenix in 2009 =  p = 130e^{0.0205(29)}

p = 130e^{0.5945}

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Hence, the population of Orlando in 2009 was about 236,000.

b) Substitute p= 300 in (1) , we get

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2.3077= e^{0.0205t} (Divide both sides by 130)

Taking Natural log on both sides,

\ln(2.3077) = 0.0205t\\\\\Rightarrow\ t=\dfrac{\ln(2.3077)}{0.0205}

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